Marge drove 348 miles in 4.5 hours. At that rate, how many miles could she drive in 10 hours?

What is the difference between a confounding and a lurking variable?

Gennadij [26K]

Answer:

A lurking variable is a variable that has an important effect on the relationship among the variables in the study, but is not one of the explanatory variables studied. Two variables are confounded when their effects on a response variable cannot be distinguished from each other.

4 0

3 years ago

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The axis of symmetry for a function in the form f(x) = x2 + 4x − 5 is x = −2. What are the coordinates of the vertex of the grap

svetlana [45]

The vertex is (-2, -9)

7 0

4 years ago

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Let x^2-mx+24 be a quadratic with roots x_1 and x_2. If x_1 and x_2 are integers, how many different values of m are possible?

iogann1982 [59]

An equation is a statement of equality „=‟ between two expression for particularvalues of the variable. For example5x + 6 = 2, x is the variable (unknown)The equations can be divided into the following two kinds:Conditional Equation:It is an equation in which two algebraic expressions are equal for particularvalue/s of the variable e.g.,a) 2x = 3 is true only for x = 3/2 b) x2 + x – 6 = 0 is true only for x = 2, -3 Note: for simplicity a conditional equation is called an equation.Identity:It is an equation which holds good for all value of the variable e.g;a) (a + b) xax + bx is an identity and its two sides are equal for all values of x. b) (x + 3) (x + 4) x2 + 7x + 12 is also an identity which is true for all values of x.For convenience, the symbol „=‟ shall be used both for equation and identity. 1.2 Degree of an Equation:The degree of an equation is the highest sum of powers of the variables in one of theterm of the equation. For example2x + 5 = 0 1st degree equation in single variable3x + 7y = 8 1st degree equation in two variables2x2 – 7x + 8 = 0 2nd degree equation in single variable2xy – 7x + 3y = 2 2nd degree equation in two variablesx3 – 2x2 + 7x + 4 = 0 3rd degree equation in single variablex2y + xy + x = 2 3rd degree equation in two variables1.3 Polynomial Equation of Degree n:An equation of the formanxn + an-1xn-1 + ---------------- + a3x3 + a2x2 + a1x + a0 = 0--------------(1)Where n is a non-negative integer and an, an-1, -------------, a3, a2, a1, a0 are realconstants, is called polynomial equation of degree n. Note that the degree of theequation in the single variable is the highest power of x which appear in the equation.Thus3x4 + 2x3 + 7 = 0x4 + x3 + x2 + x + 1 = 0 , x4 = 0are all fourth-degree polynomial equations.By the techniques of higher mathematics, it may be shown that nth degree equation ofthe form (1) has exactly n solutions (roots). These roots may be real, complex or amixture of both. Further it may be shown that if such an equation has complex roots,they occur in pairs of conjugates complex numbers. In other words it cannot have anodd number of complex roots.A number of the roots may be equal. Thus all four roots of x4 = 0are equal which are zero, and the four roots of x4 – 2x2 + 1 = 0Comprise two pairs of equal roots (1, 1, -1, -1)

8 0

4 years ago

21. Who is closer to Cameron? Explain.

pickupchik [31]

Problem 21

<h3>Answer: Jamie is closer</h3>

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Explanation:

A = Arthur's location = (20,35)
J = Jamie's location = (45,20)
C = Cameron's location = (65,40)

To find out who's closer to Cameron, we need to compute the segment lengths AC and JC. Then we pick the smaller of the two lengths.

We use the distance formula to find each length

Let's find the length of AC.

$A = (x_1,y_1) = (20,35)\\\\C = (x_2,y_2) = (65,40)\\\\d = \text{Distance from A to C} = \text{length of segment AC}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(20-65)^2 + (35-40)^2}\\\\d = \sqrt{(-45)^2 + (-5)^2}\\\\d = \sqrt{2025 + 25}\\\\d = \sqrt{2050}\\\\d \approx 45.2769257\\\\$

The distance from Arthur to Cameron is roughly 45.2769257 units.

Let's repeat this process to find the length of segment JC

$J = (x_1,y_1) = (45,20)\\\\C = (x_2,y_2) = (65,40)\\\\d = \text{Distance from J to C} = \text{length of segment JC}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(45-65)^2 + (20-40)^2}\\\\d = \sqrt{(-20)^2 + (-20)^2}\\\\d = \sqrt{400 + 400}\\\\d = \sqrt{800}\\\\d \approx 28.2842712\\\\$

Going from Jamie to Cameron is roughly 28.2842712 units

We see that segment JC is shorter than AC. Therefore, Jamie is closer to Cameron.

=================================================

Problem 22

<h3>Answer: Arthur is closest to the ball</h3>

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Explanation:

We have these key locations:

A = Arthur's location = (20,35)
J = Jamie's location = (45,20)
C = Cameron's location = (65,40)
B = location of the ball = (35,60)

We'll do the same thing as we did in the previous problem. This time we need to compute the following lengths:

AB
JB
CB

These segments represent the distances from a given player to the ball. Like before, the goal is to pick the smallest of these segments to find out who is the closest to the ball.

The steps are lengthy and more or less the same compared to the previous problem (just with different numbers of course). I'll show the steps on how to get the length of segment AB. I'll skip the other set of steps because there's only so much room allowed.

$A = (x_1,y_1) = (20,35)\\\\B = (x_2,y_2) = (35,60)\\\\d = \text{Distance from A to B} = \text{length of segment AB}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(20-35)^2 + (35-60)^2}\\\\d = \sqrt{(-15)^2 + (-25)^2}\\\\d = \sqrt{225 + 625}\\\\d = \sqrt{850}\\\\d \approx 29.1547595\\\\$

Segment AB is roughly 29.1547595 units.

If you repeated these steps, then you should get these other two approximate segment lengths:

JB = 41.2310563

CB = 36.0555128

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So in summary, we have these approximate segment lengths

AB = 29.1547595
JB = 41.2310563
CB = 36.0555128

Segment AB is the smallest of the trio, which therefore means Arthur is closest to the ball.

3 0

3 years ago

Miyoko's goal is to earn more than this week. She earns for every day she works as a cryptographer, and

Kaylis [27]

Answer:

$250*C + $180*G = $950

Step-by-step explanation:

Solving for G, it is G = (950 - 250C)/180

Solving for C, it is C = (950 - 180G)/250

6 0

3 years ago