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3 years ago

How many milliliters of olive oil (D=0.92 g/mL) have the same mass as 1.80 L of gasoline (D= .74 g/mL)

Mathematics

1 answer:

True [87]3 years ago

5 0

Answer:

1448 mL

Step-by-step explanation:

The mass is the same.

Formula

m = d*V

Givens

Olive Oil

d = 0.92 grams / mL

V = ??

Gasoline

d = 0.74 grams / mL

V = 1.8 L = 1.8 L * (1000 ml / L)

V = 1800 mL

Solution

0.74 * 1800 mL = 0.92 * x Divide both sides by 0.92

0.74/0.92 * 1800 mL = 0.92 *x / 0.92 Combine the left

0.8043 * 1800 mL = x

x = 1448 mL

The volume of Olive Oil needed is 1448 mL

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20% of Ms. Martin's class did not complete their homework. If there are 30 students in her class, how many did not complete home

padilas [110]

Answer:

Step-by-step explanation:

20% of 30 is 6

Words: 6 Students in Ms. Martin's class did not do their homework.

hope this helps :)

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2 years ago

Cal is buying T-shirts and shorts. T-shirts cost $12 and shorts cost $25. He plans on spending no more than $160 and wants to bu

Semenov [28]

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3 years ago

What lists all integer solutions of the inequality |x|<2

Nookie1986 [14]

Answer:

The solution to that inequality is (-2,2).

Step-by-step explanation:

Given the inequality |x|<2, we have two possibilities

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3 years ago

Complete the table of values for y=2x+3

Elena-2011 [213]

$y = - 2047 \\ x = - 10125$

Step-by-step explanation:

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3 years ago

For the equation given below, evaluate y′ at the point (−2,2) xe^y−4y=2x−4−2e^2

jeka94

Implicit differentiation
chain rule is important here

I'll show the steps partially
$e^y+xe^yy'-4y'=2$
$xe^yy'-4y'=2-e^y$
$y'(xe^y-4)=2-e^y$
$y'=\dfrac{2-e^y}{xe^y-4}$
now evaluate for (-2,2)
x=-2 and y=2
$y'=\dfrac{2-e^2}{-2e^2-4}$
$y'=\dfrac{2-e^2}{-2e^2-4}$
$y'=\dfrac{e^2-2}{2e^2+4}$
that's it, simplest form

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4 years ago