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vodomira [7]
2 years ago
7

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER

Mathematics
1 answer:
seropon [69]2 years ago
4 0
Assuming that the label only covers the body of the cylinder and not the circular faces on the top and bottom.

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What is 60% of 250?????
Ray Of Light [21]
Well, what you would do is 60% of 150, you'd change the if to a multiplication sign. 60/100x150/1. then follow the photo. I THINK!!

5 0
3 years ago
Read 2 more answers
There are 8 pencils in a package. How many packages will be needed for 28 children if each child gets 4
tester [92]
Roughly 102 cases is the answear
4 0
2 years ago
A submarine lies 3 kilometers from the path of a target ship. The sub’s torpedoes have a range of 5 kilometers. For what distanc
aev [14]

The distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

Explanation:

The submarine lies 3 km from the target ship.

Let B denotes the target ship and C denotes the submarine.

Let AC denotes the the target ship would be within the range of the torpedoes.

The image attached below illustrates that the distance between submarine and the target ship and the range of the torpedoes.

Let BC denotes the distance between the target ship and the submarine. Let AC denotes the range of the torpedoes.

To determine the length of AB, let us use Pythagorean theorem,

AC^{2} =AB^{2} +BC^{2}

Substituting the values of BC = 3 and AC = 5, we have,

5^{2} =AB^{2} +3^{2}

Squaring the terms, we get,

25 =AB^{2} +9

Subtracting both sides by 9, we have,

16 =AB^{2}

Taking square root on both sides,

AB = 4

Thus, the distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

5 0
3 years ago
Find y intercept of the linear equation y-5=2(x-4)
GenaCL600 [577]

Answer: y=2x-3

Step-by-step explanation:

y-5=2(x-4)

y-5=2x-8

y=2x+5-8

y=2x-3

6 0
2 years ago
Simplify the expression using the rules for
german

Step-by-step explanation:

(a×b^-3×c^-3)⁵ / (a^-3×b⁴×c⁴)^-5

let's look at the numerator (the top) first :

a⁵×b^-15×c^-15

and now the denominator (the bottom) :

a¹⁵×b^-20×c^-20

both divided are (due to the commutative rules of multiplication we can split this first into the parts of the individual variables, and then multiply them all with each other) :

a⁵/a¹⁵ = 1/a¹⁰

b^-15 / b^-20 = b^(-15 ‐ -20) = b⁵

c^-15 / c^-20 = c⁵

so we get as result :

b⁵c⁵/a¹⁰

6 0
2 years ago
Read 2 more answers
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