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Mkey [24]
3 years ago
5

The standard form of the equation of a parabola is y = x2 - 8x + 29. What is the vertex form of the equation?

Mathematics
2 answers:
Bess [88]3 years ago
7 0
Y = x² - 8x + 29
y = (x² -8x +4²) + 29 -4² . . . . add and subtract the square of half the x-coefficient
y = (x -4)² + 13 . . . . . . . . . . . . simplify

The appropriate choice is
  C. y = (x - 4)² + 13
Oxana [17]3 years ago
6 0

Answer:

y=(x-4)^2 + 13

Step-by-step explanation:

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What is the value for y in the following expression y=-2x+8 when x=20
ale4655 [162]

Answer:

<h3>y = -32</h3>

Step-by-step explanation:

y=-2x+8\\\\x=20

Substitute ; x =20 in given equation

y =-2(20 )+8\\\\y = -40+8\\\\y = -32

5 0
3 years ago
Read 2 more answers
What is the value of the expression below?
lukranit [14]

Answer:

D. 30

Step-by-step explanation:

-5(-8)(3)(-1) /(-4)

Lets simplify the numerator first

-5*-8 = 40

40 *3 = 120

120*-1 = -120

Replace -5(-8)(3)(-1)  with -120

-120/-4

A negative divided by a negative is a positive

30

8 0
3 years ago
The square of a sum of six and a number
nika2105 [10]
6x to the power of 2
6x^2

Answer: 36x
8 0
3 years ago
1. find the equation of the circle with center at (-3,1) and through the point (2,13)
daser333 [38]
Try this solution:
Common view of the equation of the circle is (x-a)²+(y-b)²=r², where point (a;b) is centre of the circle, r - radius.
1. using the coordinates of the centre and point (2;13) it is possible to define the radius of the circle: r=√(5²+12²)=13;
the equation is (x+3)²+(y-1)²=13² or (x+3)²+(y-1)²=169;
2. using the coordinates of the centre and the radius: (x-2)²+(y-4)²=6² or (x-2)²+(y-4)²=36.
7 0
3 years ago
I need help!!!
Rus_ich [418]

Answer:

-2x+y = 4

y = 2x+4

Slope = 2                      y-intercept = 4

8 0
3 years ago
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