Answer:
the inverse for each relation:
1. {(1,-2), (2, 3),(3, -3),(4, 2)} is
<u>{</u><u>(</u><u>-</u><u>2</u><u>,</u><u>1</u><u>)</u><u>,</u><u>(</u><u>3</u><u>,</u><u>2</u><u>)</u><u>,</u><u>(</u><u>-</u><u>3</u><u>,</u><u>3</u><u>)</u><u>,</u><u>(</u><u>2</u><u>,</u><u>4</u><u>)</u><u>}</u><u>.</u>
Answer:
1. D. 20, 30, and 50
2. A. 86
3. B. 94
Step-by-step explanation:
1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.
The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.
Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.
Thus:
Q1 = (85 + 87)/2 = 86
Q3 = (93 + 95)/2 = 94
IQR = Q3 - Q1 = 94 - 86
IQR = 8
Outliers in the data set are data values below the lower limit or above the upper limit.
Let's find the lower and upper limit.
Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74
The data values below the lower limit (74) are 20, 30, and 50
Let's see if we have any data value above the upper limit.
Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106
No data value is above 106.
Therefore, the only outliers of the data set are:
D. 20, 30, and 50
2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.
Thus:
Q1 = (85 + 87)/2 = 86
3. Q3 = (93 + 95)/2 = 94
Answer:
The smaller number is: 8
The bigger number is: 20
Step-by-step explanation:
Ok let's say the two numbers are x and y.
x is the smaller one, and y is the bigger one.
This is the equation to find x:
x + 4y = 88
x + y = 28
x - x + 4y - y = 88 - 28
3y = 60
y = 20
x + 20 = 28
x = 8
Answer:
A. 165 ft²
Step-by-step explanation:
volume = (½×5×6) x 11
= 15 × 11
= 165 ft²
$0.25 = 5 bottles
Divide both sides by 5:
$0.05 = 1 bottle
Last week: $12.75
12.75 = 0.05b where b represents bottles
Divide all by 0.05 to get b alone:
255 = b
