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Brrunno [24]
3 years ago
13

Which of the following is an example of independent events?

Mathematics
2 answers:
shutvik [7]3 years ago
5 0

Answer:

C. I think

Step-by-step explanation:

34kurt3 years ago
5 0

Answer: D. Rolling a 6 on the number cube and spinning a 7 on the spinner.

This is assuming that neither device touches one another when being used. The outcome of the dice will have a probability 1/6 since there is 1 side we want out of 6 total. The spinner's probability is 1/n where n is the number of sections (each section being equal in area).

Choices A and B are dependent events because of the phrasing that the item is not put back. The second selection's probability will be altered if you do not replace the first selection. So we can rule these out.

Choice C is dependent because if you own cows, then you are most likely on a dairy farm. The same is even more true in reverse because a dairy farm is defined to be one where cows are present to produce dairy products. If you know one event is true, then it leads to a higher probability the other event is true. One event is linked to the other.

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Twenty-four students took a test. Fourteen students earned an A and 10 students earned a B. A student will be randomly chosen.
Alex_Xolod [135]
The probability of a student that earned an A on the test is 7/12.

To get a fraction like this, you put the number of students on the left, or the top and the number of students total on the right, or bottom. Then, you simplify your answer. This brings us to 7/12. You cannot simplify any further because the fraction includes a prime number.


I hope this helps!
6 0
3 years ago
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Domain and range of Y=2x-1
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Step-by-step explanation:

it would be 34y i got right answer

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Negative plus positive equals
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A negative plus a positive equals a negative

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3 years ago
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Composition of functions Find g (f(x)) for the following problems
beks73 [17]

1.

f(x)=-3x\qquad g(x)=5x-6\\\\g(f(x))=5(-3x)-6=\boxed{-15x-6}

2.

f(x)=x-6\qquad g(x)=x^2+6x-2\\\\g(f(x))=(x-6)^2+6(x-6)-2=x^2-12x+36+6x-36-2=\\\\=\boxed{x^2-6x-2}

3.

f(x)=4x+3\qquad g(x)=2x^2-x+1\\\\g(f(x))=2(4x+3)^2-(4x+3)+1=2(16x^2+24x+9)-4x-3+1=\\\\=32x^2+48x+18-4x-3+1=\boxed{32x^2+44x+16}

4.

f(x)=2x^2\qquad g(x)=8x^2+3x\\\\g(f(x))=8(2x^2)^2+3(2x^2)=8\cdot4x^4+6x^2=\boxed{32x^4+6x^2}

7 0
3 years ago
Solve this question. a/7-3<0
valkas [14]

Answer:

\boxed{\sf{a

Step-by-step explanation:

You only need to isolate the term a to solve this problem.

Add by 3 from both sides.

\sf{\dfrac{a}{7}-3+3

Solve.

0+3=3

a/7<3

Multiply by 7 from both sides.

\sf{\dfrac{7a}{7}

Solve.

3*7=21

<u>a<21</u>

As a result, the solution is a<21, which is our answer.

7 0
2 years ago
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