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mestny [16]
3 years ago
9

is recommended that a ramp have least feet of horizontal distance for every 1 foot of horizontal rise along an incline. The ramp

shown has a vertical rise of 3 feet. Does the ramp shown match the recommended specifications ? Explain . Click the icon to view the ramp .

Mathematics
1 answer:
lesya [120]3 years ago
8 0

Answer: no

Step-by-step explanation:

You might be interested in
Jane is standing at the base of a 6300ft tall mountain. If she climbs 15% of the remaining height each day, how many feet will s
Andrews [41]

Answer:

Total ft climbed= 3,011.36

Step-by-step explanation:

<u>Giving the following information:</u>

Total ft= 6,300

Climbing rate= 15% of the remaining height per day

<u>Total ft climbed per day:</u>

Day 1= 6,300*0.15= 945

Day 2= (6,300 - 945)*0.15= 803.25

Day 3= (5,355 - 803.25)*0.15= 682.76

Day 4= (4,551.75 - 682.76)*0.15= 580.35

Total ft climbed= 3,011.36

4 0
3 years ago
Find the 22nd term of the following sequence:<br> 5, 8, 11, ...<br> 63 <br> 71<br> 14<br> 68
Wittaler [7]

68 is the 22nd term of the following sequence.

<u>Step-by-step explanation:</u>

  • The given sequence is with the same common difference between the two consecutive number in the series thus it is said to be the  Arithmetic progression ( AP).
  • For finding the nth term in the AP we have a formula tn = a + (n-1) × d
  • Here a is the first term , n is the number of the term to be founded and d is the common difference between the two consecutive number in the series.
  • Thus here tn = 5 + ( 22 - 1 ) × 3.
  • On subtracting we get tn = 5 + (21 ) × 3
  • On multiplying we get tn = 5 + 63
  • After adding we get tn = 68. It is the 22nd term in the given series.
5 0
3 years ago
HELPPPPPPPP how do you do this?
V125BC [204]
Solve for y like the top equation:
2y = -4ax + 11
2y/2 = -4ax/2 + 11/2
y = -2ax + 11/2

7 0
3 years ago
CAN YOU HELP ME PLEASEEEE ITS GEOMETRY!!! THANK YOUUU
SVEN [57.7K]

Answer:

117

Step-by-step explanation:

The angles line up~ P is the same as angel I.

5 0
2 years ago
You are at a stall at a fair where you have to throw a ball at a target. There are two versions of the game. In the first
Tomtit [17]

Answer:

P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729

And the probability of loss with the first wersion is 0.729

P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Alternative 1

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=3, p=0.1)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We can find the probability of loss like this P(X=0) and if we find this probability we got this:

P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729

And the probability of loss with the first wersion is 0.729

Alternative 2

Let Y the random variable of interest, on this case we now that:

Y \sim Binom(n=5, p=0.05)

The probability mass function for the Binomial distribution is given as:

P(Y)=(nCy)(p)^y (1-p)^{n-y}

Where (nCx) means combinatory and it's given by this formula:

nCy=\frac{n!}{(n-y)! y!}

We can find the probability of loss like this P(Y=0) and if we find this probability we got this:

P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

4 0
3 years ago
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