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3 years ago

9

is recommended that a ramp have least feet of horizontal distance for every 1 foot of horizontal rise along an incline. The ramp

shown has a vertical rise of 3 feet. Does the ramp shown match the recommended specifications ? Explain . Click the icon to view the ramp .

1 answer:

lesya [120]3 years ago

8 0

Answer: no

Step-by-step explanation:

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Write (8a-^3) -2/3 in simplest form

Anna71 [15]

$(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

<em><u>Solution:</u></em>

<em><u>Given that,</u></em>

$(8a^{-3})^{\frac{-2}{3}$

We have to write in simplest form

<em><u>Use the following law of exponent</u></em>

$(a^m)^n = a^{mn}$

Using this, simplify the given expression

$(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Thus the given expression is simplified

8 0

3 years ago

Porky the pig weighs 1,125 lbs. Less than Kobe the Cow. After each gains 50lbs. Kobe the Cow will weigh ten times as much as por

Papessa [141]

Answer:

Step-by-step explanation:

Let x represent the initial weight of Porky the pig.

Porky the pig weighs 1,125 lbs less than Kobe the Cow. This means that the initial weight of Kobe the cow is

x + 1125

After each gains 50lbs. Kobe the Cow will weigh ten times as much as porky the pig. This means that

(x + 1125) + 50 = 10(x + 50)

x + 1125 + 50 = 10x + 500

10x - x = 1125 + 50 - 500

9x = 675

x = 675/9

x = 75

Porky's current weight is

75 + 50 = 125 lbs

Kobe's current weight is

(75 + 1125) + 50

= 1250 lbs

4 0

3 years ago

What is the answer please help me no links I will report because it’s not ok

Pepsi [2]

Answer: 150 minutes

5 0

3 years ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

6 0

3 years ago

Solve the system of equations:<br> y = 2x - 3<br> y = x2 - 3

Tamiku [17]

Answer:

(0, -3), (2, 1)

Step-by-step explanation:

Solve this by solving for the first variable in one of the equations, then substitute the result into the other equation.

5 0

3 years ago