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3 years ago

Micheal wants to buy 12 pens but he is short of $8.40. If he buys 9 pens, he will have $29.40 left. How much money does he have?

Mathematics

1 answer:

trapecia [35]3 years ago

6 0

All you have to do is subtract the biggest numbers i the problems.

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Round 7864 to the nearest thousand

lawyer [7]

Answer:8000

Step-by-step explanation:

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3 years ago

Which could be the vertices of triangle W? A. X(–2, 2), Y(–10, 2), Z(–6, 10) B. X(2, 2), Y(4, 2), Z(3, 4) C. X(0, 2), Y(4, 2), Z

kirill [66]

Answer:

A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T. U. V. W. X. Y. Z

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3 years ago

65qt 32 gal which is more

larisa86 [58]

There are 4 quarts in one gallon.

Divide 65 quarts by 4 to see how many gallons this is equivalent to.

65/4 = 16.25

65 quarts = 16.25 gallons, so 32 gallons would be more than 65 quarts.

32 gal > 65 quarts

is your answer.

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3 years ago

On each round, Ann and Bob each simultaneously toss a fair coin. Let Xn be the number of heads tossed in the 2n flips which occu

CaHeK987 [17]

Answer:

$P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}$

Step-by-step explanation:

In a coin toss the probability of tossing a head is 0.5 (50% head/50% tails)

If n is the number of rounds and 2n the number of coins tossed (one for each player), the probability of having m heads tossed is:

$R=\frac{2n!}{m!*(2n-m)!}$

R is the number of cases (combination of coins tossed) that gives a m number of heads. Each case has a probability of $P_{case}=0.5^{2n}$ so:

$P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}$

For example, to toss 4 heads in 5 rounds:

n=5
2n=10
m=4

$P=\frac{10!}{4!*(10-4)!}*0.5^{10}$

$P=\frac{10*9*8*7*6!}{4!*6!}*0.5^{10}$

$P=\frac{10*9*8*7}{4!}*0.5^{10}$

$P=\frac{10*9*8*7}{4!}*0.5^{10}=0.205$

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3 years ago

Find the value of given expression <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B213%20%5Ctimes%20213%7D%20" id="TexForm

Hatshy [7]

Answer:

213 Answer ..............

7 0

3 years ago

Read 2 more answers