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Phantasy [73]
2 years ago
7

Help Pls

Mathematics
2 answers:
aniked [119]2 years ago
5 0

Answer: C

Step-by-step explanation:

Vesnalui [34]2 years ago
4 0

Answer:C

Step-by-step explanation:

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oakwood has a mass of 2.85 kilograms and a volume of 4100 cubic centimeters. determine the density of oak in grams per cubic cen
bogdanovich [222]

Answer:

The density of oak is <u>0.695</u> grams per cubic centimeter.

Step-by-step explanation:

Given:

Oakwood has a mass of 2.85 kilograms and a volume of 4100 cubic centimeters.

Now, to find the density of oak in grams per cubic centimeter.

Mass (m) = 2.85 kilograms.

So, using conversion factor we convert into grams:

2.85\times 1000=2850\ grams.

Volume (v) = 4100 cubic centimeters.

Now, to get the density by using formula:

Density=\frac{mass}{volume} \\Density=\frac{m}{v}

Density=\frac{2850}{4100}

Density=0.695\ grams\ per\ cubic\ centimeter.

Therefore, the density of oak is 0.695 in grams per cubic centimeter.

6 0
3 years ago
How can you tell if a function is linear?
neonofarm [45]

Linear functions are usually of degree 1. They are a straight line. y=mx+b

3 0
3 years ago
SOMEONE PLEASE PLEASE HELP I NEED THE ANSWERS YO BOTH PF THESE PLEASE
ella [17]

Answer:

1. c; 2. d

Step-by-step explanation:

1. 2*3 = 6

2. (1.43*1000)p + (2.2*1000) = (-4.001*1000)

8 0
2 years ago
Hi can someone help me with these? 5 and 6 only though
cestrela7 [59]

Answer:

5) 2z - 15 = 9

2z.=9+15

2z =24

z =12

6) 4x-2 = 62°

4x=62°+2°

4x=64°

x=16

6 0
2 years ago
Read 2 more answers
I have nooooo clue, please help
Aleksandr-060686 [28]

Answer:

case a) x^{2}=3y ----> open up

case b) x^{2}=-10y ----> open down

case c) y^{2}=-2x ----> open left

case d) y^{2}=6x ----> open right

Step-by-step explanation:

we know that

1) The general equation of a vertical parabola is equal to

y=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open upward and the vertex is a minimum

If a<0 ----> the parabola open downward and the vertex is a maximum

2) The general equation of a horizontal parabola is equal to

x=a(y-k)^{2}+h

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open to the right

If a<0 ----> the parabola open to the left

Verify each case

case a) we have

x^{2}=3y

so

y=(1/3)x^{2}

a=(1/3)

so

a>0

therefore

The parabola open up

case b) we have

x^{2}=-10y

so

y=-(1/10)x^{2}

a=-(1/10)

a

therefore

The parabola open down

case c) we have

y^{2}=-2x

so

x=-(1/2)y^{2}

a=-(1/2)

a

therefore

The parabola open to the left

case d) we have

y^{2}=6x

so

x=(1/6)y^{2}

a=(1/6)

a>0

therefore

The parabola open to the right

3 0
3 years ago
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