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3 years ago

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Sam opened a money account that pays 3 % simple interest. He started the account with 7000$ and made no further deposits. When h

e closed the account, he had earned 1,050$ in interest. How long did he keep his account open?

1 answer:

Novosadov [1.4K]3 years ago

8 0

He kept his account open for 3 years

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The largest prime factor of thirty-five is _____.

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Answer:

Prime Factor: A factor that is a prime number or it must be a whole number greater than 1.

or in other words we can say that any of the prime numbers that can be multiplied to give the original number.

To find the largest prime factor of 35.

First find the factor of 35.

Factors defined as for any numbers that we can multiply together to get another number.

Factor of 35 is; 1, 5 ,7, 35.

Now, the prime factor of 35 is 5 , 7.

Therefore, the largest prime factor of 35 is, 7.

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Without graphing, determine whether the system of linear equations has one solution, infinitely many solutions, or no solution.

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First equation :

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$a_2x {}^{2} + b_2x + c_2 = 0$

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3 years ago

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A civil engineer is analyzing the compressive strength of concrete. Compressive strength is approximately normally distributed w

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Answer:

a) $3250-1.96\frac{31.623}{\sqrt{18}}=3232.108$

$3250+1.96\frac{31.623}{\sqrt{18}}=3267.892$

So on this case the 95% confidence interval would be given by (3232.108;3267.892)

b) For this case since the value of 3270 is higher than the upper limit for the confidence interval so we can conclude that the true mean is not higher than 3270 at 5% of signficance. We can reject the claim at the significance level of 5%.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X= 3250$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma^2 =1000$ represent the sample standard variance

$s = \sqrt{1000}$ represent the sample deviation

n=12 represent the sample size

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$3250-1.96\frac{31.623}{\sqrt{18}}=3232.108$

$3250+1.96\frac{31.623}{\sqrt{18}}=3267.892$

So on this case the 95% confidence interval would be given by (3232.108;3267.892)

Part b

For this case since the value of 3270 is higher than the upper limit for the confidence interval so we can conclude that the true mean is not higher than 3270 at 5% of signficance. We can reject the claim at the significance level of 5%.

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3 years ago