I am confused with this question. Can you help me?
1 answer:
In point-slope form, the equation of the line is
.. y -k = m(x -h) . . . . . . for slope m and point (h, k)
You have m = -7/2 and (h, k) = (8, -28), so the point-slope equation is
.. y -(-28) = (-7/2)*(x -8)
.. y +28 = (-7/2)x +28 . . . . simplify
.. y = (-7/2)x . . . . . . . . . . . . subtract 28
To put this into standard form, we can multiply by 2, then add 7x.
.. 2y = -7x
.. 7x +2y = 0 . . . . . . . . . . . the standard form equation you want
.. y -k = m(x -h) . . . . . . for slope m and point (h, k)
You have m = -7/2 and (h, k) = (8, -28), so the point-slope equation is
.. y -(-28) = (-7/2)*(x -8)
.. y +28 = (-7/2)x +28 . . . . simplify
.. y = (-7/2)x . . . . . . . . . . . . subtract 28
To put this into standard form, we can multiply by 2, then add 7x.
.. 2y = -7x
.. 7x +2y = 0 . . . . . . . . . . . the standard form equation you want
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Answer:
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Step-by-step explanation:
You have two equations and two "unknowns" x and y.
This is an easy one. Add the two equations together, which will eliminate the y terms so you can solve for x:
2x+2y = -2
3x-2y = 12
---------------
5x = 10, so x = 2.
Now plug the 2 back into one of the equations and solve it for y.
2(2)+2y = -2
4+2y = -2
2y = -6
y = -3
