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4 years ago

What were the factor(s), levels, and treatments for this experiment?

Mathematics

1 answer:

wolverine [178]4 years ago

8 0

Step-by-step explanation:

A factor is an independent variable that is manipulated in an experiment.

Every factor has two or more levels, which are different values of the factor.

A combination of factor levels is called a treatment.

There is one factor: number of jumps.

This factor has two levels: sets of 10 and sets of 20.

For a single factor experiment, the levels are also the treatments: Jump 10 program and Jump 20 program.

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Determine if the given equations are parallel, perpendicular, or neither 4y=3x-4 and 4x+3y=-6

Kazeer [188]

Answer:

Perpindicular

Step-by-step explanation:

Solve each equation for y, or point Slope form.

y = mx + b

4y = 3x - 4 divide both sides by 4 to isolate the y.

y = 3/4x - 1

The second equation.

4x + 3y = - 6 subtract 4x from both sides

3y = -4x - 6 divide both sides by 3

y = -4/3 - 2

If you visualize line 1 having a Slope of 3/4, that is, for every 4 we move in the positive x direction, y will increase by 3, it slopes up from left to right crossing the y axis at (0,-1). The second line moves 3 in the positive x direction and decreases in y by 4, it slopes down from left to right crossing the y axis at (0,-2}.

Because the two lines have negative inverse slopes they are perpendicular. 3/4x and - 4/3x

8 0

3 years ago

a plastic puzzle in the shape of a triangular prism has bases that are equilateral triangles with side lengths of 4 inches and a

mrs_skeptik [129]

Answer:70

Step-by-step explanation:

You multiply all three numbers.

5 0

4 years ago

Geometric mean Pls help thank u

quester [9]

Answer:

Step-by-step explanation:

1). Geometric mean of a and b = $\sqrt{a\times b}$

Therefore, geometric mean of 2 and 50 = $\sqrt{2\times 50}$

= 10

2). By geometric mean theorem,

$\frac{JM}{KM}=\frac{KM}{ML}$

$\frac{6}{e}=\frac{e}{24}$

e² = 6 × 24

e = √144

e = 12

Similarly, $\frac{JL}{KJ}=\frac{KJ}{JM}$

$\frac{6+24}{d}=\frac{d}{6}$

d² = 6 × 30

d = √180

d = 6√5

And $\frac{JL}{KL}=\frac{KL}{ML}$

$\frac{6+24}{c}=\frac{c}{24}$

c² = 30 × 24

c = √720

c = 12√5

3 0

3 years ago

In order to determine the average weight of carry-on luggage by passengers in airplanes, a sample of 25 pieces of carry-on lugga

Fynjy0 [20]

To find the standard error, divide the standard deviation by the square root of the sample size

standard deviation = 7.5
sample size = 25......sqrt 25 = 5

standard error = 7.5 / 5 = 1.5 <==

6 0

3 years ago

A rocking horse has a weight limit of 60pounds. What percentage of the weight limit is 33 pounds? What percentage of the weight

bixtya [17]

Answer:

The percentage is 55% when weight limit is 33 pounds.

The percentage is 190% when weight limit is 114 pounds.

The 95% of the limit weighs 57 pounds.

Step-by-step explanation:

Given:

Weight limit of rocking horse = 60 pounds.

We need to find:

a) What percentage of the weight limit is 33 pounds.

b)What percentage of the weight limit is 114 pounds.

c) What weight is 95% of the limit.

Now Solving for a we get;

Weight limit = 33 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{33}{60}\times100 = 55\%$

Hence The percentage is 55% when weight limit is 33 pounds.

Now Solving for b we get;

Weight limit = 114 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{114}{60}\times100 = 190\%$

Hence The percentage is 190% when weight limit is 114 pounds.

Now Solving for c we get;

Percentage Weight = 95%

Now Amount of weight limit can be calculated by multiplying Percentage weight limit with total weight limit and then Dividing by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{95}{100}\times60 = 57 \pounds$

Hence The 95% of the limit weighs 57 pounds.

4 0

4 years ago