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3 years ago

X^2 -9 divided by x+3

Mathematics

1 answer:

WINSTONCH [101]3 years ago

4 0

Step-by-step explanation:

Hey, there!!

Given that,

$\frac{ {x}^{2} - 9 }{x + 3}$

{ we can write (a^2-4) as (a^2 - 2^2) also as (x^2- 9) can be written as (x^2 - 3^2)}.

$\frac{ {x}^{2} - {3}^{2} }{x + 3}$

We have a^2-b^2= (a+b) (a-b), so keep same formula on it.

$\frac{(x + 3)(x - 3)}{(x + 3)}$

(x+3) in numerator and denominator gets cancelled,

$(x - 3)$

Therefore, (x-3) is the final value.

Hope it helps...

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In basketball, hang time is the time that both of your feet are off the ground during a jump. The equation for hang time is t =

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Considering the hang time equation, it is found that Player 1 jumped 0.68 feet higher than Player 2.

<h3>What is the hang time equation?</h3>

The hang-time of the ball for a player of jump h is given by:

$t = 2\left(\frac{2h}{32}\right)^{\frac{1}{2}}$

The expression can be simplified as:

$t = 2\sqrt{\frac{h}{16}}$

For a player that has a hang time of 0.9s, the jump is found as follows:

$0.9 = 2\sqrt{\frac{h}{16}}$

$\sqrt{\frac{h}{16}} = \frac{0.9}{2}$

$(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.9}{2}\right)^2$

$h = 16\left(\frac{0.9}{2}\right)^2$

h = 3.24 feet.

For a player that has a hang time of 0.8s, the jump is found as follows:

$0.8 = 2\sqrt{\frac{h}{16}}$

$\sqrt{\frac{h}{16}} = \frac{0.8}{2}$

$(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.8}{2}\right)^2$

$h = 16\left(\frac{0.8}{2}\right)^2$

h = 2.56 feet.

The difference is given by:

3.24 - 2.56 = 0.68 feet.

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2 years ago

Polygon ABCD is dilated, rotated, and translated to form polygon A′B′C′D′. The endpoints of AB are at (0, -7) and (8, 8), and th

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Rotation and translation are rigid transformations, they don't change figure sizes. Dilation change figure sizes increasing or decreasing them by scale factor.

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