Question

X^2 -9 divided by x+3

Answer 1

Step-by-step explanation:

Hey, there!!

Given that,

$\frac{ {x}^{2} - 9 }{x + 3}$

{ we can write (a^2-4) as (a^2 - 2^2) also as (x^2- 9) can be written as (x^2 - 3^2)}.

$\frac{ {x}^{2} - {3}^{2} }{x + 3}$

We have a^2-b^2= (a+b) (a-b), so keep same formula on it.

$\frac{(x + 3)(x - 3)}{(x + 3)}$

(x+3) in numerator and denominator gets cancelled,

$(x - 3)$

Therefore, (x-3) is the final value.

Hope it helps...