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nordsb [41]
3 years ago
8

X^2 -9 divided by x+3

Mathematics
1 answer:
WINSTONCH [101]3 years ago
4 0

Step-by-step explanation:

Hey, there!!

Given that,

\frac{ {x}^{2} - 9 }{x + 3}

{ we can write (a^2-4) as (a^2 - 2^2) also as (x^2- 9) can be written as (x^2 - 3^2)}.

\frac{ {x}^{2} -  {3}^{2}  }{x + 3}

We have a^2-b^2= (a+b) (a-b), so keep same formula on it.

\frac{(x + 3)(x - 3)}{(x + 3)}

(x+3) in numerator and denominator gets cancelled,

(x - 3)

Therefore, (x-3) is the final value.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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More can be learned about equations at brainly.com/question/25537936

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