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nordsb [41]
3 years ago
8

X^2 -9 divided by x+3

Mathematics
1 answer:
WINSTONCH [101]3 years ago
4 0

Step-by-step explanation:

Hey, there!!

Given that,

\frac{ {x}^{2} - 9 }{x + 3}

{ we can write (a^2-4) as (a^2 - 2^2) also as (x^2- 9) can be written as (x^2 - 3^2)}.

\frac{ {x}^{2} -  {3}^{2}  }{x + 3}

We have a^2-b^2= (a+b) (a-b), so keep same formula on it.

\frac{(x + 3)(x - 3)}{(x + 3)}

(x+3) in numerator and denominator gets cancelled,

(x - 3)

Therefore, (x-3) is the final value.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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5/6

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1/3 x 1/5 = 8/15 then add to 3/10 and you get 5/6 simplifed

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As an office manager, you want to choose from buying a copier or renting one. You can buy one for $7000 with a fee of $30 a mont
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3 years ago
(−5)3x7(yz)4 / (3)2x2y8z2
g100num [7]

Answer:

\dfrac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}=\dfrac{-5x^5z^2}{2y^4}

Step-by-step explanation:

Given:

The expression to simplify is given as:

\frac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}

In order to simplify this, we have to use the law of indices.

1. (ab)^m=a^mb^m

So, (yz)^4=y^4z^4

Substitute this value in the above expression. This gives,

=\dfrac{(-5)3x^7y^4z^4}{(3)2x^2y^8z^2}\\\\\\=\dfrac{-15x^7y^4z^4}{6x^2y^8z^2}......(-5\times 3=15\ and\ 3\times 2=6)

Now, we use another law of indices.

2. \frac{a^m}{a^n}=a^{m-n}

So,  \frac{x^7}{x^2}=x^{7-2}=x^5,\frac{y^4}{y^8}=y^{4-8}=y^{-4}, \frac{z^4}{z^2}=z^{4-2}=z^2

Substitute these values in the above expression. This gives,

=\frac{-15}{6}\times x^5\times y^{-4}\times z^2\\\\=\frac{-5x^5y^{-4}z^2}{2}

Finally, we further simplify it using the law a^{-m}=\frac{1}{a^m}

So, y^{-4}=\frac{1}{y^4}

Therefore, the given expression is simplified as:

\dfrac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}=\dfrac{-5x^5z^2}{2y^4}

5 0
3 years ago
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