X^2 -9 divided by x+3
1 answer:
Step-by-step explanation:
Hey, there!!
Given that,
{ we can write (a^2-4) as (a^2 - 2^2) also as (x^2- 9) can be written as (x^2 - 3^2)}.
We have a^2-b^2= (a+b) (a-b), so keep same formula on it.
(x+3) in numerator and denominator gets cancelled,
Therefore, (x-3) is the final value.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
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Answer:
Attachment 1 :- x = 3/2
Attachment 2 :- m + r = 154°
Step-by-step explanation:
Attachment 1 :-
As the base 3 is same on both the sides , cancel the base 3 from both left & right side of eqn. After that we will get:-
Attachment 2 :-
PQR is a straight line . It's given that m + n = 110°
But we know that m + n + r = 180° ..............eqn.1
So substituting the value of m+n in eqn.1 gives :-
m+n+r = 180°
=> r + 110° = 180°
=> r = 180° - 110°
= 70°
It's also given that n+r = 96°
So putting the value of r in the above gives ,
n+r = 96°
=> n + 70° =96°
=> n = 96° - 70°
= 26°
Putting the value of n in eqn.1 gives
m + n = 110°
=> m + 26° = 110°
=> m = 110° - 26°
= 84°
So m + r = 84° + 70° = 154°