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garri49 [273]
3 years ago
6

A right rectangular prism has a side height of 4 cm and a volume of 48 cm cubed.

Mathematics
1 answer:
MrRissso [65]3 years ago
3 0

Answer:

15cm^2

Step-by-step explanation:

it is basic math to me.

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Steve cut a circular piece of mirror glass with the diameter of 20 cm in order to make a frame for it he needed to calculate the
Marianna [84]

Answer:

The circumference is 62.8 cm.

Step-by-step explanation:

To find the circumference, use 3.14 * 20 = 62.8

7 0
3 years ago
What are the solutions of the system 7x + 3y=-3 and y= -2*?
mafiozo [28]

Answer:

opt 4

Step-by-step explanation:

when x=0, 0+3y= -3, so y=-1    (0,-1) is solution

         when x=3 , 21+3y=-3,  3y= -3-21= -24

                                                    y= -8                  (3,-8) is also solution

8 0
3 years ago
The perimeter of a square is 4/5 what is its area
34kurt

Answer:

1/25

Step-by-step explanation:

square has 4 sides, if you add them all up you get 4/5.

1/5+1/5+1/5+1/5=4/5

so each side is 1/5

Area=length * width

A=1/5*1/5=1/25

3 0
2 years ago
Which two equations would be most appropriately solved by using the zero product property? Select each correct answer.
LekaFEV [45]
The zero product property tells us that if the product of two or more factors is zero, then each one of these factors CAN be zero.

For more context let's look at the first equation in the problem that we can apply this to: (x-3)(x+4)=0

Through zero property we know that the factor (x-3) can be equal to zero as well as (x+4). This is because, even if only one of them is zero, the product will immediately be zero.

The zero product property is best applied to factorable quadratic equations in this case.

Another factorable equation would be 2x^{2}+6x=0 since we can factor out 2x and end up with 2x(x+3)=0. Now we'll end up with two factors, 2x and (x+3), which we can apply the zero product property to.

The rest of the options are not factorable thus the zero product property won't apply to them.
3 0
3 years ago
Read 2 more answers
Jejxjdndnndndbdbdnsnbdbdb
amm1812

I have no clue ...I'm nt so good in maths
3 0
2 years ago
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