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MariettaO [177]
3 years ago
13

Elijah is selling coupon books for a school fundraiser. the coupon books sell for $11. the school gets $8 and $3 goes to elijah'

s homeroom. if elijah sold 24 coupon books, how much money did he collect? how much went to his homeroom? how much went to the school? help
Mathematics
1 answer:
Sladkaya [172]3 years ago
6 0
He collected $264.00, $72.00 went to his homeroom, and $192.00 to the school
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None of the graphs have a slope and y-intercept equal to y = x - 2.

y = x - 2 has a slope of 1 and y-intercept of -2, none of the graphs you shown have a slope of 1.
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Find the rate of interest per annum when<br> 1. P= 900<br> T= 2 years<br> S.l. = 90
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5% p.a will rate of interest

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Alex_Xolod [135]

Answer: The total amount the water change was -28 gallons by the end of the week <u>OR</u> The total amount the water changed decreased 28 gallons by the end of the week. Depending on how you want to word it.

Hope this helps!

Step-by-step explanation:

<u>Create you equation:</u>

x = the total amount the water changed

d = the amount of days

x = -4d

<u />

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The USDA conducted tests for salmonella in produce grown in California. In an independent sample of 252 cultures obtained from w
Marat540 [252]

Answer:

 The decision rule is  

Fail to reject the null hypothesis

  The conclusion is  

There no sufficient evidence to show that the proportion of salmonella in the region’s water differs from the proportion of salmonella in the region’s wildlife

Step-by-step explanation:

From the question we are told that

   The first  sample size is n_1   =  252

    The number that tested positive is  k_1  =  18

     The second sample size is  n_2   =  476

     The number that  tested positive is  k_2 =  20

     The level of significance is  \alpha  = 0.01

Generally the first sample proportion is mathematically represented as

      \^ p _1 =  \frac{k_1 }{ n_1 }

=>    \^ p _1 =  \frac{18 }{ 252 }

=>    \^ p _1 = 0.071

Generally the second sample proportion is mathematically represented as

      \^ p _2 =  \frac{k_2 }{ n_2 }

=>    \^ p _2 =  \frac{20 }{ 476}

=>    \^ p _2 = 0.042

The  null hypothesis is            H_o  :  p_1 - p_2 = 0

The alternative hypothesis is  H_a :  p_1 - p_2 \ne 0

Generally the test statistics is mathematically represented

       z =  \frac{ \^ p_1 - \^ p_2  -  ( p_ 1 - p_2 )}{ \sqrt{\frac{\^ p_1 (1-\^ p_1)}{ n_1  } + \frac{\^ p_2 (1-\^ p_2)}{ n_2  }  } }

=>    z =  \frac{ 0.071 - 0.042  - 0 }{ \sqrt{\frac{0.071  (1-0.071)}{  252  } + \frac{0.042 (1-\^ 0.042)}{ 476  }  } }

=>    z =  1.56

From the z table  the area under the normal curve to the right corresponding to  1.56   is  

        P(Z >  1.56 ) =0.05938

Generally the p-value is mathematically represented as

         p-value =  2 * P(Z >  1.56 )

=>      p-value = 2 *  0.05938

=>      p-value = 0.1188

From the value obtained we see that   p-value  >  \alpha hence

  The decision rule is  

Fail to reject the null hypothesis

  The conclusion is  

There no sufficient evidence to show that the proportion of salmonella in the region’s water differs from the proportion of salmonella in the region’s wildlife

 

5 0
2 years ago
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