Answer:
721
Step-by-step explanation
700 divided by 100 is 7.
So you have 7 hundred and 7 times 3 is 21.
700+21=721
This is an incomplete question, here is a complete question and image is also attached below.
How much longer is the hypotenuse of the triangle than its shorter leg?
a. 2 ft
b. 4 ft
c. 8 ft
d. 10 ft
Answer : The correct option is, (b) 4 ft
Step-by-step explanation:
Using Pythagoras theorem in ΔACB :


Given:
Side AC = 6 ft
Side BC = 8 ft
Now put all the values in the above expression, we get the value of side AB.



Now we have to calculate the how much longer is the hypotenuse of the triangle than its shorter leg.
Difference = Side AB - Side AC
Difference = 10 ft - 6 ft
Difference = 4 ft
Therefore, the 4 ft longer is the hypotenuse of the triangle than its shorter leg.
Answer:
Step-by-step explanation:
The domain of a function is all the allowed x values that make the function defined. There is nothing to make this function undefined. So the domain is negative infinity to positive infinity. All those x values are in the domain. In order to show your work, just show yourself plugging in those numbers.
You get 9, 0, and 1
Answer:
11.4
Step-by-step explanation:
So we know that Triangle ACB is similar to Triangle EFD.
This means that their sides are proportional to each other.
We want to find x or side AB. To do so, we can set up a proportion.
The proportional side to AB is ED. Let's also use BC since we know its value. The proportional side to BC is DF. Thus:

Substitute x for AB, 3.8 for Ed, 15 for BC, and 5 for DF. Thus:

Reduce the right:

Cross multiply:

So, the value of x is 11.4
And we're done!
You can use the distance formula:
d=sqroot(x2-x1)squared + (y2-y1)squared.
Plug in values: d=sqroot(8-(-6))squared + (2-2)squared
Simplify: d=sqroot(196)+0
Simplify:d=sqroot(196
Square Root: d=14 units