<span>jika xy = 0 , kemudian menganggap x dan y = 0
faktor 2x^2-9+7
(2x-2)(x-7)=0
2x-2=0
2x=2
x=1
x-7=0
x=7
</span><span>jika 1 = x1 dan 7 = x2 maka jawabannya adalah 1^2+7^2-4(1)(7)=22
</span>
jika 7 = x1 dan 1 = x2 maka jawabannya adalah
7^2+7^2-4(7)(1)=22
<span>jawabannya adalah 22</span>
<u>Answer:</u>
- The first four terms are <u>4</u><u>,</u><u>8</u><u>,</u><u>1</u><u>2</u><u>,</u><u>1</u><u>6</u>
<u>Step-by-Step </u><u>Explanation</u><u>:</u>
The given relation between the nth term and it's previous term is given by:
GiveN:
Now finding the other three terms of the AP with the given relation.
Putting a1 = 4,
Now, Third term:
Putting a2 = 8,
Now, Fourth term:
Putting a3 = 12,
Hence, The first four terms of the AP is 4, 8, 12 & 16.
Answer:
-7j-k-1
Step-by-step explanation:
A^2 - b^2 = (a-b)(a+b)
To test it, expand the right hand side.
5.75+3(.50) because it’s 5.75 and then add .50 3 times to get 7.75. Meaning you can play 3 games...
Hope that helps