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enot [183]
3 years ago
10

Simplify 10x -(-7+6x)

Mathematics
2 answers:
igor_vitrenko [27]3 years ago
4 0
That’ll be : 10x + 7 - 6x
10x - 6x + 7
4x + 7
azamat3 years ago
3 0
4x+7 is the simplified answer
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Lady bird [3.3K]

Answer:

The resulting function is g(x) = \log_{2} (x+5)-4.

Step-by-step explanation:

Let f(x) a real function, we define the following function operations:

Horizontal translation

g(x) = f(x + a) (1)

If a > 0, then horizontal translation is to the left, otherwise it is to the right.

Vertical translation

g(x) = f(x) + a (2)

If a> 0, then vertical translation is upwards, otherwise it is downwards.

Knowing that f(x) = \log_{2}x and g(x) is the result of translating f(x) four units downwards and five units to the left. Then, we find that:

g(x) = \log_{2} (x+5)-4

The resulting function is g(x) = \log_{2} (x+5)-4.

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Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt
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Answer:

y(x)=4a\sqrt{3}* sin(x)-3a

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}

But:

\frac{1}{tan(x)} =cot(x)

So:

\frac{dy(x)}{dx} =cot(x)*(3a+y)

Multiplying both sides by dx and dividing both sides by 3a+y:

\frac{dy}{3a+y} =cot(x)dx

Integrating both sides:

\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx

Evaluating the integrals:

log(3a+y)=log(sin(x))+C_1

Where C1 is an arbitrary constant.

Solving for y:

y(x)=-3a+e^{C_1} sin(x)

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y(x)=C_1*sin(x)-3a

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