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3 years ago

Write 1/3 of 7 as a mixed number.

Mathematics

2 answers:

vaieri [72.5K]3 years ago

6 0

Answer:

22/3

Step-by-step explanation:

Ipatiy [6.2K]3 years ago

5 0

Answer:

Step-by-step explanation:

Divide using long division. The whole number portion will be the number of times the denominator of the original fraction divides evenly into the numerator of the original fraction, and the fraction portion of the mixed number will be the remainder of the original fraction division over the denominator of the original fraction.

2 1/3

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Someone, please help me with this question! thank you

Anvisha [2.4K]

Answer: 8f + 4g

Step-by-step explanation:

Its distributive property.

Multiply both the 4 and 2 by the 2 from the outside then add the appropriate symbols

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3 years ago

Is 103 perfect square? show your work

alexgriva [62]

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Sarah sold a total of 178 t shirts and posters at a festival. She sold 46 more tshirts than poster. How many posters did she sel

ycow [4]

Sarah sold 66 posters

Solution:

Let "a" be the number of shirts sold

Let "b" be the number of posters sold

Sarah sold a total of 178 t shirts and posters at a festival

Therefore,

number of shirts sold + number of posters sold = 178

a + b = 178 ----------- eqn 1

She sold 46 more tshirts than poster

Number of shirts sold = 46 + number of posters sold

a = 46 + b --------- eqn 2

Substitute eqn 2 in eqn 1

46 + b + b = 178

2b = 178 - 46

2b = 132

b = 66

Thus she sold 66 posters

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3 years ago

What is e=mc^2 for m?

34kurt

M = mass

So E = mc^2 is
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3 years ago

There are big spenders among University of Alabama football season ticket holders. This data set Roll Tide!! shows the dollar am

Bas_tet [7]

Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:

$n = 479, \pi = \frac{130}{479} = 0.2714$

Hence the bounds of the interval are found as follows:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 - 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.2316$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 + 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.3112$

The 95% confidence interval is (0.2316, 0.3112).

More can be learned about the z-distribution at brainly.com/question/25890103

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2 years ago