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kenny6666 [7]
3 years ago
10

There are 16 teams in a tournament. if during the first round, each team plays every other team exactly once, how many games wil

l be played in the first round?
Mathematics
1 answer:
jasenka [17]3 years ago
5 0
16x17=272/2=136. That is answer.
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R/18 = 1/9 r=?<br> helpppp
yaroslaw [1]

Answer:

r = 2

Step-by-step explanation:

r/18 = 1/9

r = 1 * 18 /9

r = 18/9

r = 2

6 0
2 years ago
Read 2 more answers
For a two week period, John and Amanda had the following transactions occur to their checking account: a deposit of $1,644.50; c
Andru [333]

deposit of $1644.50 is (gain)

check written and deposit are (loses)  subtracted


so total of 3 checks :-   190$   +  45$  +  7.50$   =   242.50$

total of 4 debit cards :-    30$  +  5.59$  +  7.20$  + 21.30$  = 64.09$

total lose amount ( credits + debits )  =   242.50 $  +  64.09$ =  306.59$


Ending balance = Total amount - total loses =  

         1644.50$ -  306.59 $ =  1337.91$

4 0
3 years ago
Derivative of (2x+5)^4(5x+2)^-2
Sveta_85 [38]
Use chain rule

\frac{d}{dx}f(x)g(x)=f'(x)g(x)+g'(x)f(x)

and also power rule
\frac{d}{dx} x^m=mx^{m-1}

so

well, we will say f(x)=(2x+5)^4 and g(x)=(5x+2)^{-2}
f'(x)=4(2x+5)^3(\frac{d}{dy}(2x+5))=4(2x+5)^3(2)=8(2x+5)^3
g'(x)=-2(5x+2)^{-3}(\frac{d}{dx}(5x+2))=-2(5x+2)^{-3}(5)=-10(5x+2)^{-3}


so
\frac{d}{dx}(2x+5)^4(5x+2)^{-2}=8(2x+5)^3(5x+2)^{-2}+(-10(5x+2)^{-3})(2x+5)^4)
simplify yourself
3 0
3 years ago
Which number is an integer? <br><br> A: -9,248.3<br> B: -16/17 <br> C: 10,839<br> D: 35,749.087
tatiyna
The correct answer is c!
8 0
2 years ago
23.0833333333 in fraction form
Black_prince [1.1K]

Answer:

230833333333/10000000000

Step-by-step explanation:

Well to write this as a fraction you will first write 23.0833333333 as our numerator

Now you would multiply numerator by denominator which you could put 1 as denominator and multiply by 10 and you get your whole number/your answer.

Hope this helps have a great day:)

4 0
2 years ago
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