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3 years ago

A students walks at a rate of 4 miles per hour to school. If she leaves her

Physics

1 answer:

Sidana [21]3 years ago

4 0

Answer:

30 minutes or 1/2 hour

she'll get there at 8:10am but that's not important

Explanation:

u can divide 4mph by two to find how long it would take her to travel 2 miles

she travels at 2 miles per 1/2 hour

hope this helps chu <3

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What is the acceleration caused by gravity of the planet Earth?

Luda [366]

The general accepted value of acceleration due to gravity, g, is 9.81 m/s^2.

That is an approximation because being the acceleration of gravity due to the attraction of the earth its magnitude will depend on the distance from the point to the center of the planet Earth.

The value of g is determined by using the Newton's Universal Law of gravity:

F = G * m of Earth * m of body / (distance^2)

Wehre {G* m of Earth / (distance^2) } = g

G is a universal constant = 6.67 * 10 ^ -11 N*m^2 / kg^2

m of Earth = 5.98 * 10 ^ 24 kg

distance = radius of Earth + height of the body

Given the the Earth is not a perfect sphere the radius varies. Also the height of the body varies.

If you take a mean radius of Earth of 6.37*10^6 m

you get

g = 6.67*10^-11 N*m^2/kg^2 * 5.98*10^24kg / (6.37*10^6 m)^2 = 9.83 m/s^2

Again, if you want a more precise value of g, you need to find the exact place where you are and then use the right r.

7 0

3 years ago

What items can be classified as matter?

Agata [3.3K]

Gas , Liquid , or solid

7 0

4 years ago

A sample of 20.0 moles of a monatomic ideal gas (γ = 1.67) undergoes an adiabatic process. The initial pressure is and the initi

Alexeev081 [22]

There are some missing data in the text of the exercise. Here the complete text:
"<span>A sample of 20.0 moles of a monatomic ideal gas (γ = 1.67) undergoes an adiabatic process. The initial pressure is 400kPa and the initial temperature is 450K. The final temperature of the gas is 320K. What is the final volume of the gas? Let the ideal-gas constant R = 8.314 J/(mol • K). "

Solution:

First, we can find the initial volume of the gas, by using the ideal gas law:
</span> $pV=nRT$
<span>where
p is the pressure
V the volume
n the number of moles
R the gas constant
T the absolute temperature

Using the initial data of the gas, we can find its initial volume:
</span> $V_i = \frac{nRT_i}{p_i} = \frac{(20.0 mol)(8.31 J/molK)(450 K)}{4 \cdot 10^5 Pa} =0.187 m^3$
<span>
Then the gas undergoes an adiabatic process. For an adiabatic transformation, the following relationship between volume and temperature can be used:
</span> $TV^{\gamma-1} = cost.$
<span>where </span> $\gamma=1.67$ for a monoatomic gas as in this exercise. The previous relationship can be also written as
$T_i V_i^{\gamma-1} = T_f V_f^{\gamma-1}$
where i labels the initial conditions and f the final conditions. Re-arranging the equation and using the data of the problem, we can find the final volume of the gas:
$V_f = V_i \sqrt[\gamma-1]{ \frac{T_i}{T_f} }=(0.187 m^3) \sqrt[0.67]{ \frac{450 K}{320 K} }=0.310 m^3 = 310 L$
So, the final volume of the gas is 310 L.

5 0

3 years ago

A proud new Jaguar owner drives her car at a speed of 25 m/s into a corner. The coefficients of friction between the road and th

ehidna [41]

Answer:

ac = 3.92 m/s²

Explanation:

In this case the frictional force must balance the centripetal force for the car not to skid. Therefore,

Frictional Force = Centripetal Force

where,

Frictional Force = μ(Normal Force) = μ(weight) = μmg

Centripetal Force = (m)(ac)

Therefore,

μmg = (m)(ac)

ac = μg

where,

ac = magnitude of centripetal acceleration of car = ?

μ = coefficient of friction of tires (kinetic) = 0.4

g = 9.8 m/s²

Therefore,

ac = (0.4)(9.8 m/s²)

5 0

3 years ago

What is the total current for the parallel circuit?

Anton [14]

Answer:

$\huge\boxed{\sf Current = 6\ Ampere}$

Explanation:

<u>In a parallel circuit, Total resistance is:</u>

$\displaystyle \frac{1}{R_T} =\frac{1}{R_1} +\frac{1}{R_2}$

Where $R_1$ = 6Ω and $R_2$ = 12Ω

<h3><u>Finding </u> $R_T\\$ <u>:</u></h3>

$\displaystyle \frac{1}{R_T} =\frac{1}{6} +\frac{1}{12} \\\\\frac{1}{R_T} =\frac{1 \times 2+1}{12} \\\\\frac{1}{R_T} =\frac{3}{12} \\\\\frac{R_T}{1} = \frac{12}{3} \\\\\boxed{R_T=4 \ Ohm}$

<h3><u>Finding current:</u></h3>

V = 24 V, R = 4 Ω (V given, R found)

24 = I(4)

Divide 4 to both sides

6 A = I

Current = 6 Ampere

$\rule[225]{225}{2}$

8 0

2 years ago