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Anettt [7]
4 years ago
13

A radioactive nucleus has a half-life of 5*108 years. Assuming that a sample of rock (say, in an asteroid) solidified right afte

r the solar system formed, approximately what fraction of the radioactive element should be left in the rock today? The age of the solar system is 4.5*109 years. (No calculator is necessary, but if it helps use it.)
Physics
1 answer:
Gre4nikov [31]4 years ago
7 0

Answer:

0.002

Explanation:

The half-life of the radioactive nucleus is related to its quantity, by the following equation:

N_{t} = N_{0}2^{-t/t_{1/2}}

<u>Where:</u>

<em>N(t): is the quantity of the radioactive nucleus at time t</em>

<em>N₀: is the  initial quantity of the radioactive nucleus</em>

<em>t: is the time = 4.5x10⁹ years</em>

<em>t(1/2): is the half-life of the radioactive nucleus = 5x10⁸ years</em>

\frac{N_{t}}{N_{0}} = 2^{-4.5 \cdot 10^{9} y/5 \cdot 10^{8} y} = 2 \cdot 10^{-3}

Therefore, the fraction of the radioactive element in the rock today is 0.002.

I hope it helps you!  

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Potassium is a crucial element for the healthy operation of the human
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Answer:

1

  The mass of the Potassium-40 is  m_{40}} = 2.88*10^{-6} kg

2

  The Dose per year in Sieverts is   Dose_s = 26.4 *10^{-10}

Explanation:

From the question we are told that

   The isotopes of potassium in the body are Potassium-39, Potassium-40, and Potassium- 41

    Their abundance is 93.26%, 0.012% and 6.728%

   The mass of potassium contained in human body is  m = 3.0 g = \frac{3}{1000} = 0.0003 \ kg per kg of the body

    The mass of the first body is  m_1 = 80 \ kg

Now the mass of  potassium  in this body is mathematically evaluated as

       m_p =  m * m_1

substituting value

       m_p =  80  * 0.0003

      m_p  =0.024 kg

The amount of Potassium-40 present  is mathematically evaluated as

      m_{40}} =0.012% * 0.024

      m_{40}} = \frac{0.012}{100}  * 0.024

      m_{40}} = 2.88*10^{-6} kg

The dose of energy absorbed per year is mathematically represented as

          Dose  = \frac{E}{m_1}

Where E is the energy absorbed which is given as E = 1.10 MeV = 1.10 * 10^6 * 1.602*10^{-19}

    Substituting value

            Dose  = \frac{ 1.10 * 10^6 * 1.602*10^{-19}}{80}

            Dose  = 22*10^{-10} J/kg

The Dose in Sieverts is evaluated as

       Dose_s = REB * Dose

       Dose_s = 1.2 * 22*10^{-10}

       Dose_s = 26.4 *10^{-10}

             

3 0
3 years ago
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