Please help me with the attachment

A bank loaned out $8200, part of it at a rate of 7.9% per year and the rest of it at a rate of 7.4% per year. The total amount o

Lady bird [3.3K]

The amount that the bank loaned out at 7.9% is $1,574.00

How do represent the amounts lent at different rates?

On the assumption that x amount was loaned at 7.9% and that the remaining amount, (8,200-x) was loan out at 7.4%, we can determine the interest charged on each loan as the loan multiplied by the interest rate

interest on 7.9% loan=7.9%*x=0.079x

interest on 7.4% loan=7.4%*(8200-x)

interest on 7.4% loan=606.80-0.074x

total interest=0.079x+606.80-0.074x

total interest=0.005x+606.80

total interest on loans=614.67

614.67=0.005x+606.80

614.67-606.80=0.005x

7.87=0.005x

x=7.87/0.005

x=amount loaned at 7.9%=$1,574.00

y=$8200-$1574

y=$6,626.00

Find out more about bank loan interest rate on:brainly.com/question/20796174

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3 0

1 year ago

5 wars of corn for $1.55. What was the cost per ear?

Delvig [45]

Answer:

$0.31

Step-by-step explanation:

1.55/5=0.31

So if each ear of corn cost $0.31 than 5 times .31 should equal $1.55

5x.31=1.55

Yes!

7 0

3 years ago

The ratio of boys to girls in the entire 6th grade is 3 to 2. Given this ratio, which two class compositions are possible?

gtnhenbr [62]

Answer:

There's an infinite number of possible answers because there might be any multiplication of 3 for boys and any multiplication of 2 for girls. So, for example:

There might be 3 boys and 2 girls.

There might be 6 boys and 4 girls.

There might be 9 boys and 6 girls.

There might be 12 boys and 8 girls.

etc...

In each case the ratio stays the same - 3 : 2.

Of course there probably can't be more than a few dozens of people in one class, but theoretically we can raise the numbers up to infinite.

Step-by-step explanation:hope this help.

7 0

3 years ago

A survey showed that 77% of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. If 22 adults are

Sveta_85 [38]

Answer:

The probability that no more than more than 11 of them need correction for their eyesight is 0.00512

No, 11 is not a significantly low low number of adults requiring eyesight correction .

Step-by-step explanation:

A survey showed that 77% of adults need correction for their eyesight.

If 22 adults are randomly selected, find the probability that no more than more than 11 of them need correction for their eyesight.

n =22

p = 0.77

q = 1-p = 1- 0.77=0.23

We are supposed to find $P(x\leq 11)$

$P(x\leq 11)=P(x=1)+P(x=2)+P(x=3)+.....+P(x=11)$

Formula : $P(x=r)=^nC_r p^r q^{n-r}$

$P(x\leq 11)=^{22}C_1 (0.77)^1 (0.23)^{22-1}+^{22}C_2 (0.77)^2 (0.23)^{22-2}+^{22}C_3 (0.77)^1 (0.23)^{22-3}+.....+^{22}C_{11} (0.77)^1 (0.23)^{22-11}$

Using calculator

$P(x\leq 11)=0.00512$

So, The probability that no more than more than 11 of them need correction for their eyesight is 0.00512

No, 11 is not a significantly low low number of adults requiring eyesight correction .

3 0

3 years ago

7-3 x -2 / 5 + (-3)^3 using order of operations

Scrat [10]

Decimal form: 18.8
Mixed number: -18 4/5
Exact form: -94/5

6 0

3 years ago