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2 years ago

Y + 2x = 4 How do I complete this?

1 answer:

3 0

To solve this, what you will need to do is find the solution of one variable and then substitute it and solve for the other.

Here’s how to solve:
y+2x=4
-2x -2x

y=4-2x

4-2x + 2x =4

4=4

So if you’re trying to see if it is true, then your answer is that it’s true.

If you’re trying to find the linear equation, then your answer is y=-2x+4.

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Write the word sentence as an equation. Then solve.

gtnhenbr [62]

The equation is $c-13=-2$

The solved equation is 11

First, we must add 13 on both sides

$c=11$

The answer to the equation is $c=11$

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3 years ago

Rewrite 8y - 1/2 (4y - 16) in a different form

worty [1.4K]

Answer:

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2 years ago

Find the missing side of the triangle

Katena32 [7]

$\\ \sf\longmapsto sin\theta=\dfrac{Perpendicular}{Hypotenuse}$

$\\ \sf\longmapsto sin74=\dfrac{n}{40}$

$\\ \sf\longmapsto n=40sin74$

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2 years ago

Which has no real roots?

Alexxandr [17]

bruh where the problom tho

4 0

3 years ago

the numbers 1,2,3,4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacet. find t

Tresset [83]

Consider such events:

A - slip with number 3 is chosen;

B - the sum of numbers is 4.

You have to count $Pr(A|B).$

Use formula for conditional probability:

$Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.$

1. The event $A\cap B$ consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event $A\cap B$ is

$Pr(A\cap B)=\dfrac{1}{20}.$

2. The event $B$ consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event $B$ is

$Pr(B)=\dfrac{2}{20}=\dfrac{1}{10}.$

3. Then

$Pr(A|B)=\dfrac{\frac{1}{20} }{\frac{1}{10} }=\dfrac{1}{2}.$

Answer: $\dfrac{1}{2}.$

5 0

3 years ago