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Anvisha [2.4K]
2 years ago
15

How much simple interest would be earned on a certificate of deposit worth

Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
7 0

Answer:

Interest = $208

Step-by-step explanation:

At the end of 5 years, your savings will have grown to $2,208.

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An object is traveling at a steady speed of 9 9/10 km/per hour about how long will it take the object to travel 5/1/10 km/per ho
Delicious77 [7]

Answer:

0.52 km

Step-by-step explanation:

We are given that

Speed of object, v=9\frac{9}{10}km/h

Speed of object, v=9+0.9=9.9km/h

Distance travel by object, s=5\frac{1}{10}km

Distance travel by object, s=5+0.1=5.1km

We have to find the time taken by object to travel 5 1/10 km.

We know that

Time=\frac{Distance}{speed}

Using the formula

Time taken by object to travel 5.1 km =\frac{5.1}{9.9} hr

Time taken by object to travel 5.1 km=0.52 hr

8 0
2 years ago
Two young sumo wrestlers decided to go on a special diet to gain weight rapidly. They each gained weight at a constant rate. The
Radda [10]

Answer: the first wrestler gains more at the beginning, the second wrestler gains more faster

Step-by-step explanation:

5 0
3 years ago
FInd the GCF of the numbers using prime factorizations.
lesya [120]

Answer:

GCF(330, 75, 450, 225) = 15

Steps:

Prime factorization of the numbers:

330 = 2 × 3 × 5 × 11

75 = 3 × 5 × 5

450 = 2 × 3 × 3 × 5 × 5

225 = 3 × 3 × 5 × 5

GCF(330, 75, 450, 225)

= 3 × 5

= 15

3 0
3 years ago
The distance from around the Earth along a given latitude can be found using the formula C=2∏r cos L , where r is the radius of
guajiro [1.7K]

Answer:

The distance reduces to 0 as you go from 0° to 90°

Step-by-step explanation:

The question requires you to find the distance using different values of L and check the trend of the values.

Given C=2×pi×r×cos L where L is the latitude  in ° and r is the radius in miles then;

Taking r=3960 and L=0° ,

C=2×\pi×3960×cos 0°

C=2×\pi×3960×1

C=7380\pi

Taking L=45° and r=3960 then;

C= 2×\pi×3960×cos 45°

C=5600.28\pi

Taking L=60° and r=3960 then;

C=2×\pi×3960×cos 60°

C=3960\pi

Taking L=90° and r=3960 then;

C=2×\pi×3960×cos 90°

C=2×\pi×3960×0

C=0

Conclusion

The values of the distance from around the Earth along a given latitude decreases with increase in the value of L when r is constant

7 0
3 years ago
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I need help with math
Mashutka [201]

Answer:

45%

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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