Answer:
20000*(1+15%)³=30417.5
Explanation:
The number $40000 is irrelevant. Don't be disturbed!
This is a typical compound interest question. Use the compound interest formula: S=p(1+<em>i)ⁿ</em>
S for sum, p for principal balance, <em>i </em>for interest rate, n for the number of years or times
England is known for their monarchial system of government. Patrick Henry use persuasive language in the passage when;
- He appeals to emotion by asserting that his proposal is the only way to avoid enslavement by the British monarchy.
- He appeals to logic by asking his audience to look back at history for evidence of how the British government is likely to act towards them in the future.
The classical argument is known to consist of different parts. The order are;
- Exordium: This is the introduction, opening, or hook
- Narratio: This is known as the context or background of the topic
- Proposito and Partitio: This is known as the claim or the argument etc.
In the passage, Henry engages his audience by paying them respect. He acknowledge, recognizes and praise the patriotism and abilities of the other members of the Convention.
Learn more about this Passage from
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Edgeunity sample response:
<span> First, the student should estimate the cost of attending a two-year program. Then she should plan to save part of that cost. Finally, she should determine how much to budget for periodic deposits.</span>
The calculated pH of the solutions are given below:
- The pH of the solution after 14.0 ml of base is added to it is calculated as 1.45.
- The pH of the solution after 19.8 ml of base is added to it is calculated as 3.0
- The pH of the solution after 20.0 ml of base is added to it is calculated as 7.
<h3>What is pH?</h3>
This is the level of acidity or alkalinity of an aqueous solution. The pH of a substances tells if its an acid, base or neutral.
HBr and NaOH while in water would dissociate and they would become H+ and OH- respectively.
Mol of HBr = Mol * Vol
= 0.200 * 20mL
= 4 mmol
A. Moles of NaOH added
= 0.2 X 14
= 2.8 mmol
Moles of H+ that did not react
= 4 - 2.8
= 1.2 mmol
1.2/1000 = 0.0012 moles
Total volume = 20 + 14
= 34 mL to litres
= 0.034 L
Molarity of H+ = 0.0012 / 0.034L
= 0.035 M
-log[0.035] = 1.45
The pH of the solution is 1.45
B. NaOH added = 19.8 * 0.2 =
3.96 mmoles
The unreacted solution
= 4.0 - 3.96
= 0.04 mmol
0.04/1000 = 0.00004 moles
Total volume = 20 + 19.8
= 39.8mL
Converted to litres = 0.0398L
Molarity = 0.00004 / 0.0398L
= 0.001
-log(0.001) = 3.0
The ph Is therefore 3.0
C. Moles of NaOH added = 0.2*20mL = 4mmol
All the H+ are going to be consumed here. This would result into a neutral solution pH = 7
<u>Complete question:</u>
20.0 mL sample of 0.200 M HBr solution is titrated with 0.200 M NaOH solution. Calculate the PH of the solution after the following volumes of base have been added.
A. 14.0 mL
B. 19.8 mL
C. 20.0 mL
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