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3 years ago

How do you do expanded form in three ways to the number 37,917,545

2 answers:

fomenos3 years ago

8 0

You can't write expanded form in three ways, but you can write that number in expanded form AND two other ways, one you just listed.

Word: thirty seven thousand, nine hundred seventeen thousand, five hundred forty five

Expanded: 30,000,000 + 7,000,000 + 900,000, 10,000 + 7,000 + 500 + 40 + 5

Standard: 37,917,545

kupik [55]3 years ago

6 0

One way 30,000,000+7,000,000+ 900,000+10,000+7,000+500+40+5

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Free_Kalibri [48]

Answer:

(a) 1,902,231,808,400

(b) 84

Step-by-step explanation:

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!\cdot(n-k)!}$

(a)

Compute the number of ways to select 9 applicants from 100 as follows:

${100\choose 9}=\frac{100!}{9!\cdot(100-9)!}$

$=\frac{100!}{9!\times 91!}\\\\=\frac{100\times 99\times 98\times 97\times 96\times 95\times 94\times 93\times 92\times 91!}{9!\times 91!}\\\\=\frac{100\times 99\times 98\times 97\times 96\times 95\times 94\times 93\times 92}{9!}\\\\=1902231808400$

(b)

Compute the number of ways to select 6 people from 9 as follows:

${9\choose 6}=\frac{9!}{6!\cdot(9-6)!}$

$=\frac{9!}{6!\times 3!}\\\\=\frac{9\times 8\times 7\times 6!}{6!\times 3!}\\\\=\frac{9\times 8\times 7}{3!}\\\\=84$

(c)

Compute the number of ways to select top 3 candidates from 6 as follows:

${6\choose 3}=\frac{6!}{3!\cdot(6-3)!}$

$=\frac{6!}{3!\times 3!}\\\\=\frac{6\times 5\times 4\times 3!}{3!\times 3!}\\\\=\frac{6\times 5\times 4}{3!}\\\\=20$

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3 years ago

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Step-by-step explanation:

Find the recursive formula (tₙ = tₙ₋₁ + d) of -4, -1, 2.

Arithmetic sequences have a common difference, "d" , between terms.

To find the common difference, subtract a term value from the term value after it.

-1 - -4 = 3

2 - -1 = 3

The common difference is 3.

To find the next term, add 3 to the previous term.

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tₙ = tₙ₋₁ + 3

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