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Anna007 [38]
3 years ago
9

Highest common factor of 72 and 90

Mathematics
1 answer:
TiliK225 [7]3 years ago
5 0

Answer:

18

Step-by-step explanation:

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Lee bought a couch for $600. He made equal payments of 10% of the total cost. How much was each payment?
vekshin1
10 % OF THE PAYMENT IS 600/10=60 DOLLARS
EACH PAYMENT WAS 60 DOLLARS<span />
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To complete such a customer at your store needs to purchase vertical brackets to attach to the wall the customer wants to show t
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67

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you have to divide

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Diane borrowed 8000 at a rate of 7%, compounded semiannually. Assuming she makes no payments, how much will she owe after 6 year
dmitriy555 [2]

Answer: $12088.55

Step-by-step explanation:

A = p(1+r/n)^nt

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7 0
4 years ago
From her purchased bags, Rory counted 110 red candies out of 550 total candies. Using a 90% confidence interval for the populati
Svetlanka [38]

Answer:

The Confidence Interval = (0.172, 0.228)

Where:

The lower limit = 0.172

The upper limit = 0.228

Step-by-step explanation:

The formula to be applied or used to solve this question is :

Confidence Interval formula for proportion.

The formula is given as :

p ± z × √[p(1 - p)/n]

n = Total number of red candies = 550 red candles

p = proportion = Number of red candies counted/ Total number of red candies

= 110/550 = 1/5 = 0.2

z = z score for the given confidence interval.

We are given a confidence interval of 90%. Therefore, the z score = 1.6449

Confidence Interval = p ± z × √[p(1 - p)/n]

Confidence Interval = 0.2 ± 1.6449 × √[0.2(1 - 0.2)/550]

= 0.2 ± 1.6449 √0.2 × 0.8/550

= 0.2 ± 1.6449 × 0.0170560573

= 0.2 ± 0.0280555087

Hence, the Confidence Interval = 0.2 ± 0.0280555087

0.2 - 0.0280555087 = 0.1719444913

Approximately = 0.172

0.2 + 0.0280555087 = 0.2280555087

Approximately = 0.228

Therefore, the Confidence Interval = (0.172, 0.228)

Where:

The lower limit = 0.172

The upper limit = 0.228

4 0
3 years ago
Match with the sum of the monomial and binomial. Tiles 2x2y + (x2y − 2xy2) (5xy2 − x2y) + 3x2y 4x2y + (x2y + xy2) x2y + (-2xy2 −
SVETLANKA909090 [29]
<h2>Answer:</h2>

We will simply solve them and get correct answers that will match the answers provided.

1.  2x^{2}y+(x^{2}y-2xy^{2} )

= 3x^{2} y-2xy^{2}

2. (5xy^{2}-x^{2} y)+3x^{2} y

= 5xy^{2} +2x^{2} y

3. 4x^{2} y+(x^{2} y+xy^{2} )

= 5x^{2} y+xy^{2}

4. x^{2} y+(-2xy^{2}-4x^{2} y)

= -3x^{2} y-2xy^{2}

3 0
4 years ago
Read 2 more answers
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