Rotating a polygon in Quadrant II 270° clockwise is the same as what?
1 answer:
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Answer:
I assume you know Arithmetic Progression .
so, we have to find the first and last 4-digit number divisible by 5
first = 1000 , last = 9990
we have a formula, = a + (n-1)d
here, is the last 4-digit number divisible by 5.
n is the number of 4-digit even numbers divisible by 5
d is the common difference between the numbers, which is 10 in this case
a is the first 4-digit number divisible by 5
9990 = 1000 + (n-1)*10
899 = n-1
n = 900
Hence, there are 900 4-digit even numbers divisible by 5
Answer:
The correct answer is,
I'm 100000000% sure.
Answer:
<h2>1.65</h2>Step-by-step explanation:
First, we find the area of the circle.
A = pi * r^2
A = pi * (1 cm)^2
A = pi cm^2
The area of the circle is pi cm^2.
The area of the triangle is also pi cm^2.
Now we use the area of a triangle.
A = (1/2)bh
(1/2)bh = A
(1/2)(3 cm)h = pi cm^2
(3 cm)h = 2pi cm^2
h = (2/3)pi cm
The exact height is
If you want an approximate height, then it is 2.09 cm.