Answer:
it would be just a little less to fit in
Step-by-step explanation:
The properties that apply true are:
1–as it implies the Pythagorean theorem; a^2+b^2=c^2
3–as it implies the basic rules of visualized geometry.
4–as the greater side(hypotenuse) is opposite the right angle.
NOT 2, as the accrue angles ARE complimentary.
Answer:
a) 
b) 394 thousand = 394,000 people will be following the website in 2016
Step-by-step explanation:
Exponential equation for an amount:
The exponential equation for an amount after t years has the following format:

In which y(0) is the initial value and r is the growth rate, as a decimal.
A social media website had 350,000 followers in 2010. The number y of followers increases by 2% each year.
This means that: 
a. Write an exponential growth function that represents the number of followers t years after 2010
In thousands:


b. How many people will be following the website in 2016?
2016 is 6 years after 2010, so this is y(6).

Rounding to the nearest thousand:
394 thousand = 394,000 people will be following the website in 2016
Answer:

Step-by-step explanation:
<u><em>Given Equation is </em></u>
=> 
Comparing it with
, we get
=> a = 2, b = 7 and c = -9
So,
Sum of roots = α+β = 
α+β = -7/2
Product of roots = αβ = c/a
αβ = -9/2
<em>Now, Finding the equation whose roots are:</em>
α/β ,β/α
Sum of Roots = 
Sum of Roots = 
Sum of Roots = 
Sum of roots = 
Sum of roots = 
Sum of Roots = 
Sum of roots = 
Sum of roots = S = 
Product of Roots = 
Product of Roots = P = 1
<u><em>The Quadratic Equation is:</em></u>
=> 
=> 
=> 
=> 
This is the required quadratic equation.
9514 1404 393
Answer:
B. 9πx^6
Step-by-step explanation:
Putting the given radius into the area formula gives ...
A = πr^2
A = π(3x^3)^2 = π(3^2)(x^(3·2))
A = 9πx^6