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2 years ago

2. it's not B

Mathematics

1 answer:

Tanzania [10]2 years ago

4 0

Answer:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

( 0 , 1 )

Equation Form:

x = 0 , y = 1

Step-by-step explanation:

Graph.

y = − 5/ 2 x − 1

y = 3 x − 1

y = 2/ 5 x + 1

y = 5/ 3 x + 1

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Someone help me with this<br> Find the 10th term of the sequence -63, -93, -123

Katarina [22]

Answer:

-333

Step-by-step explanation:

It seems like it is going down by -30 each term.

6 0

2 years ago

Write the equation of the line represented by the following table

s344n2d4d5 [400]

Answer:

y = 100x + 400

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 400) and (x₂, y₂ ) = (1, 500) ← 2 points from the table

m = $\frac{500-400}{1-0}$ = 100

note the line crosses the y- axis at (0, 400) ⇒ c = 400

y = 100x + 400 ← equation of line

4 0

2 years ago

Solve using the box method

Lena [83]

$\huge\text{Hey there!}$

$\large\text{Just SIMPLIFY the given EQUATION or find the DIFFERENCE}\\\large\text{OF the SQUARES... Here is the formula: }\mathsf{\bf a^2 - b^2 =(a+b)(a-b)}$

$\large\text{Equation: }\mathsf{\dfrac{(4x^2-9)}{(2x + 3)}}$

$\large\text{Rewrite }\mathsf{ 4x^9 - 9}\large\text{ in the formation of }\mathsf{a^2 - b^2}\large\text{ whereas}\mathsf{a = 2x \ \&\ b = 3.}$

$\large\text{Equation: }\mathsf{\dfrac{(2x)^2-3^2}{2x + 3}}$

$\large\text{This is where you try to do the DIFFERENCE OF its SQUARES}$

$\mathsf{\dfrac{(2x + 3)(2x - 3)}{2x + 3}}$

$\large\text{CANCEL out: }\mathsf{(2x + 3)\ - (2x +3)}\large\text{ because it gives you 0}$

$\large\text{This leaves us with }\mathsf{\bf 2x - 3}\large\text{ as your POSSIBLE ANSWER}$

$\boxed{\boxed{\large\text{Answer: \huge \bf 2x - 3}}}\huge\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

$\large\text{Note: There is/are many ways to solve for equations like this.... this was just}\\\large\text{the quickest and easiest way to understand it!}$