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FinnZ [79.3K]
3 years ago
9

Compare the two structural formulas in each set. Do they represent the same compound, represent constitutional isomers or repres

ent two compounds which are neither identical nor constitutional isomers
Chemistry
1 answer:
Dennis_Churaev [7]3 years ago
5 0

Answer:

(1). Both compounds are constitutional isomers.

(2). Both Compounds are constitutional isomers.

(3). Both compounds are identical isomers.

Explanation:

NB: Kindly check the attached picture for the diagram paired compounds.

The term 'constitutional isomers' means the isomers with the same molecular formula, the only difference is the way they are arrange. Constitutional isomers have the same number of elements in them, only their arrangements differs.

Constitutional isomers is also known as structural isomers and it is one of the types of isomers. The other one is stereo-isomers or spartial isomers which is also further divided.

Now, let's consider the paired chemical compounds.

(1). Both compounds are constitutional isomers.

Deduction: this are functional isomers as what differs is the arrangement of the C=O group.

(2). Both Compounds are constitutional isomers.

Deduction: the OH group is in the same position. Only the arrangement of carbon differs.

(3). Both compounds are identical isomers.

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If Ba^{+2} will reacts with N^{-3}, the formula of the compound formed is Ba_3N_2.

<h3>What is an ionic compound?</h3>

Ionic compounds are neutral compounds made up of positively charged ions called cations and negatively charged ions called anions.

Barium is a metal element and Nitrogen is a non-metal element, so they form an ionic compound. To make the formula of an ionic compound, first, we need to see the valence of the atoms, that is, how many electrons it can donate or it has to gain to have 8 electrons in the valence layer (octet rule).

Barium is in family 2, so it has two electrons in its valence layer, so it must donate these two electrons; Nitrogen is in family 15, so it has 5 electrons ins its valence layer and must gain 3 electrons.

Writing the ions they must form:

Ba^{+2}N^{-3}

First came the cation (positive charge), then the anion (negative charge), and the charges must change between them, without the signal, and will inform how many atoms are necessary for which element:

Ba_3N_2

Hence, If Ba^{+2} will reacts with N^{-3}, the formula of the compound formed is Ba_3N_2.

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Answer:

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