Question

If ba+2 will reacts with n-3, the formula of the compound formed is:

Answer 1

If $Ba^{+2}$ will reacts with $N^{-3}$, the formula of the compound formed is $Ba_3N_2$.

What is an ionic compound?

Ionic compounds are neutral compounds made up of positively charged ions called cations and negatively charged ions called anions.

Barium is a metal element and Nitrogen is a non-metal element, so they form an ionic compound. To make the formula of an ionic compound, first, we need to see the valence of the atoms, that is, how many electrons it can donate or it has to gain to have 8 electrons in the valence layer (octet rule).

Barium is in family 2, so it has two electrons in its valence layer, so it must donate these two electrons; Nitrogen is in family 15, so it has 5 electrons ins its valence layer and must gain 3 electrons.

Writing the ions they must form:

$Ba^{+2}N^{-3}$

First came the cation (positive charge), then the anion (negative charge), and the charges must change between them, without the signal, and will inform how many atoms are necessary for which element:

$Ba_3N_2$

Hence, If $Ba^{+2}$ will reacts with $N^{-3}$, the formula of the compound formed is $Ba_3N_2$.

Learn more about the ionic compound here:

brainly.com/question/9167977

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