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2 years ago

What is the difference between the cells in a single-called organism and the cells in a human body

Chemistry

1 answer:

Fed [463]2 years ago

4 0

Answer:

Unicellular organisms are made up of only one cell that carries out all of the functions needed by the organism, while multicellular organisms use many different cells to function. ... Multicellular organisms are composed of more than one cell, with groups of cells differentiating to take on specialized functions.

Explanation:

does that make any sense???

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What are the balanced chemical equations for Hydrochloric acid and potassium hydroxide?

-Dominant- [34]

HCl(aq) + KOH(s) --> KCl(aq) + H2O(l)

7 0

3 years ago

For the following reaction, 4.31 grams of iron are mixed with excess oxygen gas . The reaction yields 5.17 grams of iron(II) oxi

natka813 [3]

Answer: The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For Iron:

Given mass of iron = 4.31 g

Molar mass of iron = 53.85 g/mol

Putting values in above equation, we get:

$\text{Moles of iron}=\frac{4.31g}{53.85g/mol}=0.0771mol$

For the given chemical reaction:

$2Fe(s)+O_2(g)\rightarrow 2FeO(s)$

By Stoichiometry of the reaction:

2 moles of iron produces 2 moles of iron (ii) oxide.

So, 0.0771 moles of iron will produce = $\frac{2}{2}\times 0.0771=0.0771mol$ of iron (ii) oxide

Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

Moles of of iron (II) oxide = 0.0771 moles

Molar mass of iron (II) oxide = 71.844 g/mol

Putting values in equation 1, we get:

$0.0771mol=\frac{\text{Theoretical yield of iron(ii) oxide}}{71.844g/mol}=5.53g$

To calculate the percentage yield of iron (ii) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of iron (ii) oxide = 5.17 g

Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

$\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%$

Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

7 0

3 years ago

HELP!!! An experiment was conducted to determine if the intermolecular forces in two liquids affects their boiling points. Each

ExtremeBDS [4]

Answer: it would be b time taken by the glass surface to dry

Explanation:

i had took the test and i got it right

4 0

3 years ago

Where would the electrons in the 3d sublevel be found? Possibly in any shell only in the n = 3 energy level in energy levels &gt

postnew [5]

Answer:

In the n = 3 energy level

Explanation:

There's is no further explanation for this.

All the electrons in an energy level are distribuited according to the period in the periodic table they are.

So, if we have an atom in period 1, like Hydrogen (H), that atom would only have 1 level energy (n = 1) and in that level, we only have the sub level 1s.

Electrons in the 3d sublevel, are found mostly in all the transition metals of period 3, and it can go from 1 to 10 electrons. To be with the 3d sub level it's neccesary that the energy level to be 3.

energy levels beyond that, like n = 4, we have electrons occupying the 3d sub level, so, primordly, the 3d is found only in energy level 3.

Hope this helps

4 0

3 years ago

What's the chemical equation for the carbon dioxide bubbles in a homemade lava lamp?

julsineya [31]

Answer:

C₆H₈O₇+ 3NaHCO₃ --› Na₃C₆H₅O₇ + 3CO2 + 3H₂O

Explanation:

The reaction occuring in lava lamp is acid base reaction.

When you drop tablet into water the citric acid reacts with sodium bicarbonate and forms water, a salt, and bubbles of carbon dioxide gas.

6 0

3 years ago

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