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PilotLPTM [1.2K]
3 years ago
5

How can you find a function that has roots?

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
6 0

Answer:

The roots of a function are the x-intercepts.

Step-by-step explanation:

RUDIKE [14]3 years ago
5 0

The roots of a function are the x-intercepts. By definition, the y-coordinate of points lying on the x-axis is zero. Therefore, to find the roots of a quadratic function, we set f (x) = 0, and solve the equation, ax2 + bx + c = 0.

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4.07, 4.070, 4.70, 4.0700 what value is not equivalent.
larisa [96]
4.70, all the others can be simplified to 4.07 by taking away the zeroes after the 7 because they are not significant, The one before the 7 stays because it is significant as it is holding the tenths place value.
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I need help. PLEASE, I dont know what to do​
spayn [35]

Answer:

HELL I DON'T EATHIER

Step-by-step explanation:

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How do you use the keyboard on the computer to write exponents and other algebraic symbols
ICE Princess25 [194]

You will have to type it into Microsoft word first, type a number or algebraic expression into a Word document. Press the "Ctrl," "Shift" and "=" keys on your keyboard to turn on the Superscript mode. Enter another number or expression signifying the exponent.


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7 0
3 years ago
The equation a=1/2(b^1+b^2)h can be determined the area, a, of a trapezoid with height, h, and base lengths, b^1 and b^2 Which a
Evgesh-ka [11]

The complete question is as follows.

The equation a = \frac{1}{2}(b_1 + b_2 )h can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths, b_1 and b_2. Which are equivalent equations?

(a) \frac{2a}{h} - b_2 = b_1

(b) \frac{a}{2h} - b_2 = b_1

(c) \frac{2a - b_2}{h} = b_1

(d) \frac{2a}{b_1 + b_2} = h

(e) \frac{a}{2(b_1 + b_2)} = h

Answer: (a) \frac{2a}{h} - b_2 = b_1; (d) \frac{2a}{b_1 + b_2} = h;

Step-by-step explanation: To determine b_1:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = b_1 + b_2

\frac{2a}{h} - b_2 = b_1

To determine h:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{(b_1 + b_2)} = h

To determine b_2

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = (b_1 + b_2)

\frac{2a}{h} - b_1 = b_2

Checking the alternatives, you have that \frac{2a}{h} - b_2 = b_1 and \frac{2a}{(b_1 + b_2)} = h, so alternatives <u>A</u> and <u>D</u> are correct.

4 0
3 years ago
Can u plz help me plz?
mina [271]

6^3

that's the answer

8 0
3 years ago
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