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Korvikt [17]
3 years ago
12

PLEASE HELP!! Convert 6.4% to a decimal

Mathematics
2 answers:
snow_lady [41]3 years ago
7 0

Answer:

0.064

Step-by-step explanation:

the correct answer is 0.064

Masja [62]3 years ago
5 0
6.4% in decimal form is 0.064
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How many solutions does the following equation haves? -3x+9-2x=-12-5x
Mashcka [7]

Answer:

no solution

Step-by-step explanation:

-3x+9-2x=-12-5x\

-5x+5x=-12-9

0=-21

which is impossible.

4 0
3 years ago
During a basketball practice, Mai attempted 49 free throws and was on 25% of them. How many successful free throws did she make?
Brrunno [24]

Mai made 12 successful free throws.

Step-by-step explanation:

Given,

Free throws made by Mai = 49 free throw

Successful throws = 25%

Number of successful throws = 25% of free throws

Number of successful throws = \frac{25}{100}*49

Number of successful throws = \frac{1225}{100} = 12.25

Rounding off to nearest whole number;

Number of successful throws = 12

Mai made 12 successful free throws.

Keywords: percentage, division

Learn more about division at:

  • brainly.com/question/11150876
  • brainly.com/question/11175936

#LearnwithBrainly

6 0
4 years ago
Find the ratio. Sam ran 3520 feet in 20 minutes.
Rufina [12.5K]
3520:20 should be correct
8 0
3 years ago
Read 2 more answers
In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A
vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

\mu_s=np=500*0.90=450

The standard deviation will be:

\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

\mu=np=300*0.932=279.6

The standard deviation will be:

\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

P(270\leq x\leq280)=P(269.5

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

P(X=280)=P(279.5

8 0
3 years ago
HELPPPP IMMEDIATELY....
lana [24]
First you do what is inside the parentheses. 10 x 5 - 3. 50 - 3 =47. Then you multiply 47 x 5 = 235.
3 0
3 years ago
Read 2 more answers
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