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sasho [114]
3 years ago
10

Please help me solve

Mathematics
1 answer:
Inga [223]3 years ago
3 0

Answer:

s= -2

Step-by-step explanation:

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Trinity solved the equation 2(x-3)+7-3x=11.
lukranit [14]

Answer:

x=-10

Step-by-step explanation:

2(x-3)+7-3x=11

2\left(x-3\right)+7-3x-7=11-7

2\left(x-3\right)-3x=4

-x-6=4

-x-6+6=4+6

-x=10

\cfrac{-x}{-1}=\cfrac{10}{-1}

x=-10

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2 years ago
Last month Christopher practiced his violin for 16 hours and Patrick practiced his cello for 780 minutes how many more hours did
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Step-by-step explanation:

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3 years ago
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You and a friend play a game where you each toss a balanced coin. If the upper faces on the coins are both tails, you win $1; if
oksian1 [2.3K]

Answer:  The mean and variance of Y is $0.25 and $6.19 respectively.

Step-by-step explanation:

Given : You and a friend play a game where you each toss a balanced coin.

sample space for tossing two coins : {TT, HT, TH, HH}

Let Y denotes the  winnings on a single play of the game.

You win $1; if the faces are both heads

then P(Y=1)=P(TT)=\dfrac{1}{4}=0.25

You win $6; if the faces are both heads

then P(Y=6)=P(HH)=\dfrac{1}{4}=0.25

You loose $3; if the faces do not match.

then P(Y=1)=P(TH, HT)=\dfrac{2}{4}=0.50

The expected value to win : E(Y)=\sum_{i=1}^{i=3} y_ip(y_1)

=1\times0.25+6\times0.25+(-3)\times0.50=0.25

Hence, the mean of Y : E(Y)= $0.25

E(Y^2)=\sum_{i=1}^{i=3} y_i^2p(y_i)\\\\=1^2\times0.25+6^1\times0.25+(-3)^2\times0.5\\\\=0.25+1.5+4.5=6.25

Variance = E[Y^2]-E(Y)^2

=6.25-(0.25)^2=6.25-0.0625=6.1875\approx6.19

Hence, variance of Y = $ 6.19

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On the sea,distances are measured in nautical miles rather than miles.
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