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mezya [45]
2 years ago
8

Help plz with this

Mathematics
1 answer:
kirill115 [55]2 years ago
6 0
He is congruent to the term from the product but B is the wrong answer but I don’t know about secrecy is might be the answer so just put d
Deez nurs
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Picking a purple marble from a jar with 10 green and 10 purple marbles
sukhopar [10]

Answer:

9 purple 10 green

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd) =
BabaBlast [244]

Answer:

4c² + 11cd + 5d

Step-by-step explanation:

(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)

-4c² + 7cd + 8d - 3d + 8c² + 4cd (opening bracket)

8c²-4c²+7cd + 4cd + 8d - 3d

= 4c² + 11cd + 5d

4 0
2 years ago
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A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A
julsineya [31]

Answer:

a) -13.9 ft/s

b) 13.9 ft/s

Step-by-step explanation:

a) The rate of his distance from the second base when he is halfway to first base can be found by differentiating the following Pythagorean theorem equation respect t:

D^{2} = (90 - x)^{2} + 90^{2}   (1)

\frac{d(D^{2})}{dt} = \frac{d(90 - x)^{2} + 90^{2})}{dt}

2D\frac{d(D)}{dt} = \frac{d((90 - x)^{2})}{dt}  

D\frac{d(D)}{dt} = -(90 - x) \frac{dx}{dt}   (2)

Since:

D = \sqrt{(90 -x)^{2} + 90^{2}}

When x = 45 (the batter is halfway to first base), D is:

D = \sqrt{(90 - 45)^{2} + 90^{2}} = 100. 62

Now, by introducing D = 100.62, x = 45 and dx/dt = 31 into equation (2) we have:

100.62 \frac{d(D)}{dt} = -(90 - 45)*31          

\frac{d(D)}{dt} = -\frac{(90 - 45)*31}{100.62} = -13.9 ft/s

Hence, the rate of his distance from second base decreasing when he is halfway to first base is -13.9 ft/s.

b) The rate of his distance from third base increasing at the same moment is given by differentiating the folowing Pythagorean theorem equation respect t:

D^{2} = 90^{2} + x^{2}  

\frac{d(D^{2})}{dt} = \frac{d(90^{2} + x^{2})}{dt}

D\frac{dD}{dt} = x\frac{dx}{dt}   (3)

We have that D is:

D = \sqrt{x^{2} + 90^{2}} = \sqrt{(45)^{2} + 90^{2}} = 100.63

By entering x = 45, dx/dt = 31 and D = 100.63 into equation (3) we have:

\frac{dD}{dt} = \frac{45*31}{100.63} = 13.9 ft/s

Therefore, the rate of the batter when he is from third base increasing at the same moment is 13.9 ft/s.

I hope it helps you!

4 0
3 years ago
Read 2 more answers
Brainliest...I have to post a few of these cause I forgot to study for this assignment....
kherson [118]

Answer:

-1

Step-by-step explanation:

you do 1/1 which is 1. because the line is negative, the answer is -1

8 0
3 years ago
What is the point-slope form of a line with slope 2 that contains the point (1, 3)?
Simora [160]
\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 1}}\quad ,&{{ 3}})\quad 
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 2
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-3=2(x-1)\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
8 0
3 years ago
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