Quieres un chocolate? Please help reply correctly in Spanish
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Answer: x= ..
Step-by-step explanation: We are given a segment parallel to the base.
Therefore, sides of big triangle and small triangles would be in proportion.
Setting values for the shown triangle, we get
On cross multiplication, we get
16(2x+7) = 38(x)
32x + 112 = 38x.
Subtracting 112 from both sides, we get
32x + 112-112 = 38x -112
32x = 38x-112
Subtracting 38x from both sides, we get
32x-38x = 38x-38x-112
-6x = -112
Dividing both sides by -6, we get
x= ..
Answer:
Plot I area= 32.5cm²
Plot II area = 73.09cm²
Plot III area = 35cm²
Plot IV area = 54cm²
Total the area of Field = 194.59cm²
Step-by-step explanation:
The field is made up of four plots with different shapes. So we would find the area of the 4 shapes to get the area of the plots.
A question related to this can be found at brainly (question ID: 18861101)
Find attached the diagram
Given:
AC = 13cm
AE = 19cm
CF = DE = 7cm
AD = AE - DE
AD = 19-7 = 12cm
GF = 9cm, EH = 15cm
GH = 17cm
Plot I: A right angle triangle
Area = ½ × base × height
Base = CD, height = AD
Using Pythagoras theorem
CD = √(AC² - AD)²
CD = √(13² - 12²) = √(169-144)
CD = √25 = 5
Area = ½ × 5 ×13= 32.5
Area plot I = 32.5cm²
Plot II: An equilateral triangle
Area of the equilateral triangle = a²/4 ×(√3)
√3=1.73
a = side = AC
Area = (13)²/4 ×(√3) = 42.25 × 1.73 = 73.0925
Area of Plot II = 73.09cm²
Plot III: A rectangle
Area of a rectangle = length × width
length = 7cm
width = 5cm
Area of plot III = 7×5 = 35cm²
Plot IV: A trapezium
Area of trapezium = ½(base 1 + base2) × height
Base 1= FE = CD
Base 2= GH
To get height using diagram 2. When you draw the lines from the two points on base1, you would have 1 rectangle in the middle with the two triangles by the side.
We would apply Pythagoras theorem to find h in the two right angled triangles:
Hypotenuse ² = opposite ²+adjacent ²
1st ∆: 9² = h²+a²
h² = 81-a²
2nd ∆: 15² = h² + (12-a)²
225 = h² +144 - 24a+ a²
225-144 = h²-24a+ a²
Insert value for h² in the 2nd
81 = 81-a² - 24a + a²
24a = 81-81
a= 0
h² = 81-0²
h = √81 = 9
Area of trapezium = ½(5+7) × 9
= 6 × 9
Area of plot IV= 54cm²
Total the area of field = area of plot I + area of plot II + area of plot III +area of plot IV
= 32.5 + 73.09 + 35+ 54
Total the area of Field = 194.59cm²
