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3 years ago

What is the solution in ³√3-x=³√2x

Mathematics

1 answer:

VashaNatasha [74]3 years ago

7 0

Answer:

3√3−x=3√2x

Graph each side of the equation. The solution is the x-value of the point of intersection.

x≈0.46567646

image of graph

Step-by-step explanation:

Hope it is helpful.....

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How do you round 276,431 to the nearest ten thousand?

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Read 2 more answers

A law firm is going to designate associates and partners to a big new case. The daily rate charged to the client for each associ

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Answer: the system of equations that could be used are

700x + 1700y = 21200

y = x + 4

Step-by-step explanation:

Let x represent the number of associates assigned to the case.

Let y represent the number of partners assigned to the case.

The daily rate charged to the client for each associate is $700 and the daily rate for each partner is $1700.

The law firm was able to charge the client $21200 per day for these lawyers' services. This mean that

700x + 1700y = 21200 - - - - - - - - - - 1

The law firm assigned 4 more partners than associates to the case. This means that

y = x + 4 - - - - - - - - - - - - - - - - -2

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3 years ago

Paul has some money in his wallet, all in $1 bills. He buys a hat and has $6 left, as shown in

nirvana33 [79]

Answer:

$14

Step-by-step explanation:

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3 years ago

I really need help guys can some one plz help me it's for 10 points

11111nata11111 [884]

Answer:

$\sqrt{8}----- 2units,2units$

$\sqrt{7} ------\sqrt{5}units,\sqrt{2}units$

$\sqrt{5}-------1unit,2units$

$3------2units, \sqrt{5}units$

Step-by-step explanation:

Use pythagorean's theorem to solve each pair individually.

The instructions say that you have the two sides (a and b) and you have to match it with their hypothenuse.

$Formula: c^2=a^2+b^2$

1. $a=\sqrt{5}, b=\sqrt{2}$

Plug this into the formula.

$c=\sqrt{(\sqrt{5} )^2+(\sqrt{2})^2 }$

The square here eliminates the roots.

$c=\sqrt{5+2}\\ c=\sqrt{7}$

2. $a=\sqrt{3}, b=4$

$c=\sqrt{(\sqrt{3} )^2+(4)^2}\\ c=\sqrt{3+16}\\ c=\sqrt{19}$

3. $a=2, b=\sqrt{5}$

$c=\sqrt{(2)^2+(\sqrt{5})^2 }\\ c=\sqrt{4+5}\\ c=\sqrt{9}\\ c=3$

4. $a=2, b=2$

$c=\sqrt{(2)^2+(2)^2}\\ c=\sqrt{4+4}\\ c=\sqrt{8}$

5. $a=1, b=2$

$c=\sqrt{(1)^2+(2)^2}\\ c=\sqrt{1+4}\\ c=\sqrt{5}$

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3 years ago

What is the solution in ³√3-x=³√2x​

What is the solution in ³√3-x=³√2x