Answer:
The magnitude of an earthquake is 5.6.
Explanation:
The magnitude of an earthquake can be found as follows:
Where:
I: is the intensity of the earthquake = 37.25 cm
S: is the intensity of a standard earthquake = 10⁻⁴ cm
Hence, the magnitude is:
Therefore, the magnitude of an earthquake is 5.6.
I hope it helps you!
Answer:
kinetic energy (K.E) = 5.28 ×10⁻¹⁷
Explanation:
Given:
Mass of α particle (m) = 6.50 × 10⁻²⁷ kg
Charge of α particle (q) = 3.20 × 10⁻¹⁹ C
Potential difference ΔV = 165 V
Find:
kinetic energy (K.E)
Computation:
kinetic energy (K.E) = (ΔV)(q)
kinetic energy (K.E) = (165)(3.20×10⁻¹⁹)
kinetic energy (K.E) = 528 (10⁻¹⁹)
kinetic energy (K.E) = 5.28 ×10⁻¹⁷
Answer:
From Savos point of view, Gadros appear not to be moving
Explanation:
The given parameters are;
The distance between Godric and Savos = A few meters
The location of Godric and Savos = One end of the field
The location pf Peter = The other end pf the field
The speed with which Godric and Savos are moving towards Peter = 4 m/s
Let the positive x-direction be the direction in which Godric and Savos are moving
Therefore;
The speed and direction with which Godric is moving = The speed and direction with which Savos is moving = 4·i m/s
From Savos point of view, the relative speed with which Godric is moving = (The speed and direction in which Godric is moving) - (The speed and direction in which Savos is moving) = 4·i m/s - 4·i m/s = 0 m/s
Therefore, from Savos point of view, the relative speed with which Godric is moving = 0 m/s or Gadros appears stationary or not to moving.
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Answer:</h2>
1.68 x 10⁻⁸Ωm
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Explanation:</h2>
The resistance (R) of a wire is related to its length(L), its material resistivity(ρ) and its crossectional area(A) as follows;
R = ρL/A ------------------------(i)
Where;
A = πd² / 4 [where d = diameter of the wire]
From the question;
L = 6.90m
d = 2.15mm = 0.00215m
R = 0.0320Ω
First calculate the crossectional area (A) of the wire as follows;
A = πd² / 4
[Take π = 3.142]
d = 0.00215m
∴ A = 3.142 x (0.00215)² / 4
∴ A = 0.000003631m²
Now, substitute the values of A, L, and R into equation (i) as follows;
R = ρL/A
0.0320 = ρ x 6.90 / 0.000003631
0.0320 = 1900302.95 x ρ
Solve for ρ;
=> ρ = 0.0320 / 1900302.95
=> ρ = 1.68 x 10⁻⁸Ωm
Therefore, the resistivity of the material of the wire is 1.68 x 10⁻⁸Ωm
Answer:
Potential energy
Explanation:
Potential energy is the energy stored within an object, due to the object's position, arrangement or state. Potential energy is one of the two main forms of energy, along with kinetic energy.
