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ziro4ka [17]
2 years ago
11

__________ theory argues that city growth is generated by the pressure from the city center to expand outward. Expansion threate

ns to encroach on the surrounding areas and does so in concentric waves, or circles, with the center being the most intense, having the highest density and highest occupancy. These concentrations become progressively less intense and of lower density with greater distance from the center.
Physics
2 answers:
artcher [175]2 years ago
8 0

Answer: Concentric zone

Explanation:

PIT_PIT [208]2 years ago
5 0

Answer:

Defensible space

Explanation:

The defensible space theory states that an area can only be defined as a housing development if the people living in that location decide and defend that that area should adopt a good design and structure. For this reason, the area becomes a defensible space. In other words, the theory states that a residential area is only a successful defensible space, if the area forms a set in agreement between society and the physical elements of the region.

In addition, the theory argues that citizens should feel safe and responsible for this region, living in society and harmony.

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The ____ of a sound wave is a measure of its loudness.
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The answer to this question is amplitude
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3 years ago
The critical angle between a medium and air is 430. What is the speed of light in that medium?
vagabundo [1.1K]

Answer:

The speed of light is that medium is 281907786.2 m/s.

Explanation:

since the critical angle is Фc = 430, we know that the refractive index is given by:

n = 1/sin(Фc)

  = 1/sin(430)

  = 1.06

then if n is the refractive index of the medium and c is the speed of light, then the speed of light in the medium is given by:

v = c/n

  = (3×10^8)/(1.06)

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Therefore, the speed of light is that medium is 281907786.2 m/s.

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3 years ago
In Hooke’s law, what does the x represent?
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Assume that two of the electrons at the negative terminal have attached themselves to a nearby neutral atom. There is now a nega
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5 0
3 years ago
The instantaneous speed of a particle moving along one straight line is v(t) = ate−6t, where the speed v is measured in meters p
beks73 [17]

Answer:

v_max = (1/6)e^-1 a

Explanation:

You have the following equation for the instantaneous speed of a particle:

v(t)=ate^{-6t}   (1)

To find the expression for the maximum speed in terms of the acceleration "a", you first derivative v(t) respect to time t:

\frac{dv(t)}{dt}=\frac{d}{dt}[ate^{-6t}]=a[(1)e^{-6t}+t(e^{-6t}(-6))]  (2)

where you have use the derivative of a product.

Next, you equal the expression (2) to zero in order to calculate t:

a[(1)e^{-6t}-6te^{-6t}]=0\\\\1-6t=0\\\\t=\frac{1}{6}

For t = 1/6 you obtain the maximum speed.

Then, you replace that value of t in the expression (1):

v_{max}=a(\frac{1}{6})e^{-6(\frac{1}{6})}=\frac{e^{-1}}{6}a

hence, the maximum speed is v_max = ((1/6)e^-1)a

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3 years ago
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