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3 years ago

7

The length and breadth of a rectangular room are 5m and 3.2m. Find the cost carpeting the room at the rate of $500 per square me

tre

1 answer:

ollegr [7]3 years ago

6 0

The answer is 800 bc it is

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What is the range of 34, 56, 13, 98, 75

Crank

The range is the highest number minus the lowest number

98 - 13 = 85 <==

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3 years ago

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11000 is compounded semiannually at a rate of 12% for 21 years. Find the total amount in the compound interest account

marishachu [46]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\dotfill &\$11000\\
r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus twice}
\end{array}\dotfill &2\\
t=years\dotfill &21
\end{cases}$

$\bf A=11000\left(1+\frac{0.12}{2}\right)^{2\cdot 21}\implies A=11000(1.06)^{42}\implies A\approx 127127.359416$

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3 years ago

A raindrops has a mass of 0.50g. how many moles of water does a raindrop contain

alina1380 [7]

So, here you have to look at the periodic table and see what the molar mass of each molecule composing the water compound $H_2 O$
its two hydrogen atom plus an oxygen molecule, making it about 18g per mol.

That said, looking at the mass, we have to ask ourselves, if a mol of water contains 18g of mass, how many moles do we have in 0.5g of water?
We just do a cross multiplication:
$\frac{(0.5)}{18} =0.027 mol$

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3 years ago

A random sample of 16 statistics examinations was taken. The average sample score was 76.2 with a sample variance of 144. The 99

dlinn [17]

99% confidence interval for the population average examination score is between a lower limit of 67.35 and an upper limit of 85.05. The correct option is C.

<h3>What is the margin of error in statistics?</h3>

The margin of error is a statistic that describes how much random sampling error there is in survey results. One should have less faith that a poll's findings would accurately reflect those of a population census the higher the margin of error.

The interval will be calculated as below:-

Confidence interval = mean +/- margin of error (E)

mean = 76.2

variance = 144

sd = sqrt(variance) = sqrt(144) = 12

n = 16

Degree of freedom (df) = n - 1 = 16- 1 = 15

Confidence level (C) = 99% = 0.99

Significance level = 1 - C = 1 - 0.99 = 0.01 = 1%

t-value corresponding to 15 df and 1% significance level is 2.95

The margin of error will be:-

E = t×sd/√n = 2.95 × 12/√16 = 8.85

The interval will be:-

Lower limit = mean - E = 76.2 - 8.85 = 67.35

Upper limit = mean + E = 76.2 + 8.85 = 85.05

Therefore, the 99% confidence interval for the population average examination score is between a lower limit of 67.35 and an upper limit of 85.05. The correct option is C.

To know more about margin of error follow

brainly.com/question/24289590

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2 years ago

(-6u+3c+4)+(5u-5c)<br> help me please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

tigry1 [53]

-6u+3c+4+5u-5c
-1u-2c+4

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3 years ago

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