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KatRina [158]
2 years ago
8

What is 15/8 equal to?

Mathematics
2 answers:
yKpoI14uk [10]2 years ago
6 0

Answer:

1.875

Step-by-step explanation:

i hope this helps, have a good day!

Paraphin [41]2 years ago
3 0
1.857


AhhhhhhHhHhHh
Eekkkkkkkkkk Lol
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Area =  area of rectangle - area of 2 hemispheres
         = 24 * 32 - pi * 12^2
         = 315.6  sq units
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3 years ago
Please help 50 points!<br> Simplify the expressed
LenKa [72]

Answer:

Step-by-step explanation:

\frac{x^{2} -x-12}{x+4} * \frac{2x^{2}-32 }{x^{2} -8x+16}  rewrite as multiplication

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\frac{x(x+3)-4(x+3)}{x+4} * \frac{2(x-4)(x+4) }{(x-4)^{2}}  , difference of 2 squares and perfect square

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2(x+3)

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2 years ago
The smiths have saved $25,000 toward the purchase of a new car. If the sales tax is 5%, the purchase price of smiths new car bef
lukranit [14]

Answer:

26,250

Step-by-step explanation:

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8 0
3 years ago
Southern Oil Company produces two grades of gasoline: regular and premium. The profit contributions are $0.30 per gallon for reg
Contact [7]

Answer:

a) MAX--> PC (R,P) = 0,3R+ 0,5P

b) <u>Optimal solution</u>: 40.000 units of R and 10.000 of PC = $17.000

c) <u>Slack variables</u>: S3=1000, is the unattended demand of P, the others are 0, that means the restrictions are at the limit.

d) <u>Binding Constaints</u>:

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

Step-by-step explanation:

I will solve it using the graphic method:

First, we have to define the variables:

R : Regular Gasoline

P: Premium Gasoline

We also call:

PC: Profit contributions

A: Grade A crude oil

• R--> PC: $0,3 --> 0,3 A

• P--> PC: $0,5 --> 0,6 A

So the ecuation to maximize is:

MAX--> PC (R,P) = 0,3R+ 0,5P

The restrictions would be:

1. 18.000 A availabe (R=0,3 A ; P 0,6 A)

2. 50.000 capacity

3. Demand of P: No more than 20.000

4. Both P and R 0 or more.

Translated to formulas:

Answer d)

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

To know the optimal solution it is better to graph all the restrictions, once you have the graphic, the theory says that the solution is on one of the vertices.

So we define the vertices: (you can see on the graphic, or calculate them with the intersection of the ecuations)

V:(R;P)

• V1: (0;0)

• V2: (0; 20.000)

• V3: (20.000;20.000)

• V4: (40.000; 10.000)

• V5:(50.000;0)

We check each one in the profit ecuation:

MAX--> PC (R,P) = 0,3R+ 0,5P

• V1: 0

• V2: 10.000

• V3: 16.000

• V4: 17.000

• V5: 15.000

As we can see, the optimal solution is  

V4: 40.000 units of regular and 10.000 of premium.

To have the slack variables you have to check in each restriction how much you have to add (or substract) to get to de exact (=) result.  

3 0
3 years ago
Find the gradient (m) and y-intercept (c) of the equation y =-2/3x+1/3
zepelin [54]

he equation of a line is written as y=mx+b where m is the slope and b is the

y -intercept, Thus,m=23 And the y -intercept,b=1

4 0
3 years ago
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