The length is 10
The width is 4
4 + 6 = 10
4 x 10 = 40
2*5=10 (the measure of one long side is 10)
3*4=12 (the measure of one wide side is 12)
A box has four sides to the perimeter of the flat wrapping paper must consist of four edges. Because we know that one edge is 10 inches long and another side is 12 inches wide we assume that the corresponding sides are equal.
So now we know that we have two sides that are 10 inches and 2 sides that are 12 inches.
10+10+12+12= 44 inches
105 times 15= 1575
57 times 20= 1140
1140+1575= 2715
(2715)(d)= x
x being the total amount the company paid
2
Divide both the top and bottom by 2 and you get 2/3
X=y-4 Let's make this eqn 1 and
2x-5y=3 this eqn 2..
Two things are possible here...
Its either you substitute for x in equation 2... Or you substitute for y...
x=y-4 put this in the equation 2..
2x-5y=3.. Replace the x with (y-4)
2(y-4)-5y = 3...
Since this is In the option no point in substituting for y...
Hope this helped...?
