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ehidna [41]
3 years ago
13

Find the total pay for biweekly at $9.50 per hour

Mathematics
2 answers:
beks73 [17]3 years ago
4 0

Answer:

The answer is 760

Step-by-step explanation:

If you make $9.50 an hour with 8 hours a day and 40 hours a week you multiply the 9.50 with 40 to get 380. Now, you have the total for one week you can double it to get the pay for two weeks which come out to 760.

PilotLPTM [1.2K]3 years ago
3 0

how many hours do they work? Please be more spesific

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garik1379 [7]
The area of a parallelogram is the base times the height
9 × 5.2
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3 0
3 years ago
Read 2 more answers
Answer my questions plz help
coldgirl [10]

9514 1404 393

Answer:

  • a = -2/3, b = 8, c = -24
  • y-intercept: (0, -24)
  • x = -b/(2a) = -8/(2(-2/3)) = 8(4/3)
  • x = 6
  • DOWN
  • Max: (6, 0)
  • Vertex: (6, 0)
  • Domain: {x | x ∈ ℝ}
  • Range: {x | x ≤ 0}

Step-by-step explanation:

To find a, b, c, compare the given function to ...

  f(x) = ax² +bx +c

You will see that ...

  • a = -2/3
  • b = 8
  • c = -24

The y-intercept is the function value for x=0. It is the constant term:

  y-intercept = f(0) = -24

Use the above values of a, b to find the line of symmetry.

  x = \dfrac{-b}{2a}=\dfrac{-8}{2\cdot\dfrac{-2}{3}}=8\cdot\dfrac{3}{4}=6

Per the calculation, the line of symmetry is ...

  x = 6

The negative leading coefficient tells you the parabola opens DOWN.

Because it opens down, the vertex at (6, 0) is a Maximum.

As with any polynomial, the domain is "all real numbers", hence any x that is an element of Reals.

The range is all values below the vertex (including the vertex), so is ...

  x ≤ 0

3 0
2 years ago
5. Two angles are supplements if their sum is 180 degrees. The measurement of one angle is five more than six times its suppleme
ankoles [38]
25 degrees would be the smaller angle
5 0
3 years ago
For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with l
murzikaleks [220]

Answer:

The answer is "0.68".

Step-by-step explanation:

Given value:

X_i \sim \frac{G_1}{2}

E(X_i)=2 \\

Var (X_i)= \frac{1- \frac{1}{2}}{(\frac{1}{2})^2}\\

             = \frac{ \frac{2-1}{2}}{\frac{1}{4}}\\\\= \frac{ \frac{1}{2}}{\frac{1}{4}}\\\\= \frac{1}{2} \times \frac{4}{1}\\\\= \frac{4}{2}\\\\=2

Now we calculate the \bar X \sim N(2, \sqrt{\frac{2}{n}})\\

\to \frac{\bar X - 2}{\sqrt{\frac{2}{n}}}  \sim  N(0, 1)\\

\to \sum^n_{i=1}  \frac{X_i - 2}{n}  \times\sqrt{\frac{n}{2}}}  \sim  N(0, 1)\\\\\to  \sum^n_{i=1}  \frac{X_i - 2}{\sqrt{2n}}  \sim  N(0, 1)\\

\to Z_n = \frac{1}{\sqrt{n}} \sum^n_{i=1} (X_i -2) \sim N(0, 2)\\

\to P(-1 \leq X_n \leq 2)  = P(Z_n \leq Z) -P(Z_n \leq -1) \\\\

                               = 0.92 -0.24\\\\= 0.68

6 0
3 years ago
Just need help with 6 please
alexdok [17]

Answer:

Congruent, SSS

Step-by-step explanation:

The dashes on the sides of the triangles represent that the corresponding lengths of the triangles are equal in length. Since it is given that all corresponding lengths of the triangles are equivalent, the triangles are congruent by the SSS (side, side, side) test.

Hope this helps :)

4 0
3 years ago
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