Answer:
It is a function Jonny!
Step-by-step explanation:
Hello! I would say to Jonny:
Jonny! A function is a relation between two sets, in which every element of the first set (domain) is assigned only one element of the second set (codomain).
If you have serveral elements of the first set with the same corresponding element of the second set it is correct to call that relation a function.
However, if you have an element of the first set for which your relation can relate to more than one element of the second set, then Jonny, that is not a function.
In the present case, every student ID number can only be realted to a number of the set {9, 10, 11, 12}, a student cannot have more than one current grade level. Therefore, that relation is in fact a function
Answer:
hw que no te he podido contestar por la tarde pero si te llamo en el tercero para que
For this case we have the following polynomial:
What we must do for this case is to factor the polynomial, so that we have:
1) The number of bottles
2) the weight of each bottle.
We have then:
Answer:
A factorization that could represent the number of water bottles and weight of each water bottle is:
Answer:
See answer below
Step-by-step explanation:
The statement ‘x is an element of Y \X’ means, by definition of set difference, that "x is and element of Y and x is not an element of X", WIth the propositions given, we can rewrite this as "p∧¬q". Let us prove the identities given using the definitions of intersection, union, difference and complement. We will prove them by showing that the sets in both sides of the equation have the same elements.
i) x∈AnB if and only (if and only if means that both implications hold) x∈A and x∈B if and only if x∈A and x∉B^c (because B^c is the set of all elements that do not belong to X) if and only if x∈A\B^c. Then, if x∈AnB then x∈A\B^c, and if x∈A\B^c then x∈AnB. Thus both sets are equal.
ii) (I will abbreviate "if and only if" as "iff")
x∈A∪(B\A) iff x∈A or x∈B\A iff x∈A or x∈B and x∉A iff x∈A or x∈B (this is because if x∈B and x∈A then x∈A, so no elements are lost when we forget about the condition x∉A) iff x∈A∪B.
iii) x∈A\(B U C) iff x∈A and x∉B∪C iff x∈A and x∉B and x∉C (if x∈B or x∈C then x∈B∪C thus we cannot have any of those two options). iff x∈A and x∉B and x∈A and x∉C iff x∈(A\B) and x∈(A\B) iff x∈ (A\B) n (A\C).
iv) x∈A\(B ∩ C) iff x∈A and x∉B∩C iff x∈A and x∉B or x∉C (if x∈B and x∈C then x∈B∩C thus one of these two must be false) iff x∈A and x∉B or x∈A and x∉C iff x∈(A\B) or x∈(A\B) iff x∈ (A\B) ∪ (A\C).
Answer:
Sample size minimum is 60
Step-by-step explanation:
given that you want to create a 99% confidence interval with a margin of error of .5.
The population standard deviation is equal to 1.5
i.e. 
Confidence level = 99%
Since population std deviation is known, we can use Z critical value for finding margin of error
Z critical value for 99% = 2.58
Margin of error = 
Equate this to 0.5 and solve for n
