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tresset_1 [31]
2 years ago
15

Adrian is a songwriter who collects royalties on his songs whenever they are played in a commercial or movie. Adrian will earn $

40 every time one of his songs is played in a commercial and $130 every time one of his songs is played in a movie. Adrian earned a total of $1010 in royalties on 14 commercials commercials and movies. Write a system of equations that could be used to determine the number of commercials and the number of movies on which Adrian's songs were played. Define the variables that you used to write the system.
Mathematics
1 answer:
djverab [1.8K]2 years ago
7 0

Answer:

commercial =  9

movie = 5

Step-by-step explanation:

Step one:

let the number of commercials be x and movies be y

so

40x+130y=1010-------------1

since there are a total of 14 commercials and movies combined

x+y=14--------------2

Hence the systems of equation is

40x+130y=1010------1

x+y=14-------------------2

Step two:

from equation 2

x=14-y

substui]te the value of x in  equation 1

40(14-y)+130y=1010

560-40y+130y=1010

collect like terms

130y-40y=1010-560

90y=450

divide both sides by 90

y=450/90

y=5

movies is 90

put y=5 in equation 2

x+5=14

x=14-5

x= 9

commercial is 9 in numbers

and movie is 5

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devlian [24]

Answer:

3x + 30

Step-by-step explanation:

3(x+10)\\\\\text{Distribute '3' into 'x + 10'}\\\\\\3(x+10)\rightarrow3x+30\\\\\left \{ {{3*x=3x} \atop {3*10=30}} \right.

3x + 30 would be an equivalent expression.

Hope this helps.

8 0
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brilliants [131]
C. 1700 is the correct answer.
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Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.
Andre45 [30]

Answer:

Option d)  5 to the power of negative 5 over 6 is correct.

\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}

Above equation can be written as 5 to the power of negative 5 over 6.

ie, 5^\frac{\bf -5}{\bf 6}

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}

Above equation can be written as 5 to the power of negative 5 over 6.

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