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3 years ago

Please help this is like 40% of my Grade!!

Mathematics

1 answer:

svet-max [94.6K]3 years ago

4 0

Answer:

120

Step-by-step explanation:

supplementary means the angles add up to 180

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cora says she doesn't need to know the y-intercept of a line to write its equation, just its slope and some other point on the l

Nadusha1986 [10]

Answer:

The equation of line with given slope that include given points is 3 y + x - 20 = 0

Step-by-step explanation:

According to Cora , if we know the slope and points on a line then we can write the equation of a line .

Since , The equation of line in slope-intercept form is

y = m x + c

Where m is the slope of line , and if we know the points ( x , y ) which satisfy the line then constant term c can be get and the equation of line can be formed .

So , From the statement said above it is clear that she is correct .

Now , Again

Given as :

Slope of a line is m = - $\frac{1}{3}$

That include points ( 2 , 6 )

Now from the equation of line as y = m x + c

∴ 6 = - $\frac{1}{3}$ ( 2 ) + c

Or, 6 = - $\frac{2}{3}$ + c

So , c = 6 + $\frac{2}{3}$

or, c = $\frac{18 + 2}{3}$

∴ c = $\frac{20}{3}$

So, The equation of line can be written as

y = - $\frac{1}{3}$ x + $\frac{20}{3}$

Or, 3 y = - x + 20

I.e 3 y + x - 20 = 0

Hence The equation of line with given slope that include given points is 3 y + x - 20 = 0 Answer

8 0

3 years ago

A ramp with a constant incline is made to connect a driveway to a front door. At a point 4 feet from the driveway, the height of

harkovskaia [24]

Let A(4,12) and B(6,18)

RATE OF CHANGE = m = (y₂ - y₁) / (x₂ - x₁) = (18-12)/ (6-4)

m= 6/2 or m = 3

4 0

2 years ago

Read 2 more answers

Please help I can’t figure it out

Lynna [10]

Answer:

149.71

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Prime factorisation of 500

Andrews [41]

$\boxed{\underline{\bf \: ANSWER}}$

2 | 500

2 | 250

5 | 125

5 | 25

5 | 5

1 | 1

Prime factorisation of 500 = 2 × 2 × 5 × 5 × 5 × 1

_____

Hope it helps.

ᏒᎯᎨᏁᏰᎾᏯᏕᎯᏝᎿ2222

6 0

2 years ago

What is the radical form of the expression (2x^4y^5)^3/8

s344n2d4d5 [400]

We are given expression: $(2x^4y^5)^{3/8}$

Let us distribute 3/8 over exponents in parenthesis, we get

$(2^{3/8}x^{4\times 3/8}y^{5\times 3/8}) = (2^{3/8}x^{12/8}y^{15/8})$

$= (2^{3/8}x^{1\frac{4}{8}} y^{1\frac{7}{8}} )$

We can get x and y out of the radical because, we get whlole number 1 for x and y exponents for the mixed fractions.

So, we could write it as.

$(2^{3/8}x^{1\frac{4}{8}} y^{1\frac{7}{8}} ) = xy(2^{\frac{3}{8} }x^{\frac{4}{8}} y^{\frac{7}{8}} )$

Now, we could write inside expression of parenthesis in radical form.

$xy\sqrt[8]{2x^{3}x^4y^7}$

8 0

3 years ago