Section J has 20 rows....each row has 15 seats....so section J has (20 * 15) = 300 seats. If each seat costs $ 18, and all the seats are sold, then the amount of money collected would be : (300 * 18) = $ 5,400 <=
Answer:
Step-by-step explanation:
This is a duplicate of one I have done for you
BF = 3*HF
BF = 3*6
BF = 18
Normally You would need to simplify all of them, to see what their values are like.
Already from the start, however, we can see that 9n + 3 + 2 and 9n + 11 isnt the same value. Based on this, we should only need to simplify one of the other, to get either 9n + 5 or 9n + 11.
Lets pick the upper one.
(4n + 3) + 5n + 8 - 6
4n + 3 +5n + 2
9n + 5.
This indicated that 9n+11 is the odd one.
To make sure, we can solve the next one:
(4n + 5n) + (3 + 8 - 6)
9n + 5
Which indicated the same thing.
9n+11 is the "outsider", which means:
9n + 11 is the correct answer for this task.
In radians:
To get 0, only one part of the multiplication needs to be zero for the whole thing to be zero. Thus we get 2 equations:
t=0, and cos(t)=0
for the first equation, it's pretty self-explanatory and sp we get 0 as one solution.
For the second equation, cos(pi/2) and cos(3pi/2) both equal 0 so both pi/2 and 3pi/2 are answers. Since there is no bound to this problem, the actual answer is:
(2Z+1)pi/2 and 0
(2Z+1) means all odd integers
