Question

Jeremy bakes two pans of brownies that are the same size. One pan has nuts in it and the other pan does not. He cuts the pan with nuts into 8 equal pieces. He cuts the pan without nuts into 16 equal pieces. His friends eat 2 brownies with nuts and 3 brownies without nuts. Did they eat more of the brownies with nuts or without nuts?

Answer 1

Answer:

The answer is "$\frac{2}{8} > \frac{3}{16}$ So, they eat more brownies with nuts".

Step-by-step explanation:

In the given question, the two browny pans of equal size are baked by Jeremy. There is indeed a saucepan with nuts in it, not the other pan. He split the pot into eight equal chunks with nuts. He slices the pan into 16 equal parts without nuts. His mates eat 2 nuts brownies and three nut-free brownies. They eat more nuts and brownies $\frac{2}{8} > \frac{3}{16}$ eat more.