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aivan3 [116]
2 years ago
15

Please solve this now. Everything is attached in the file. You need to provide a full solution. Thanks

Mathematics
1 answer:
Liono4ka [1.6K]2 years ago
4 0

Based on the requirements for FICA and Medicare tax, the amount to be withheld in March for FiCA is $685.10 and for Medicare is $160.23.

The amount to be withheld in December of FICA is $523.90 and for Medicare is $160.23.

<h3>How much is to be withheld for FICA?</h3>

In March, the amount to be withheld is:

= 11,050 x 6.2%

= $685.10

To find out the amount withheld in December, find out the earnings up to that point:

= 11,050 x 12

= $132,600

FICA can only be withheld on the first $130,000 so the amount of FICA In December is:

= 6.2% x ( 11,050 - (132,600 - 130,000))

= $523.90

<h3>What amount will be withheld for Medicare?</h3>

The amount will be the same for both March and December as Medicare is for all earnings:

= 11,050 x 1.45%

= $160.23

Find out more on Medicare taxes at brainly.com/question/1848671

#SPJ1

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Answer:

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Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

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[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}

[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}

[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}

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Cardiac output:F=\frac{3}{54.49}

Cardiac output:F=0.055 L\s

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Answer:

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